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bogdanovich [222]
3 years ago
11

What would the answer to this question be ? 1 - (-1)

Mathematics
2 answers:
Len [333]3 years ago
6 0
It would be two, hope this helps
shusha [124]3 years ago
3 0
The answer would be 2. when your subtracting a negative think of -(- as a +
hope it helps
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Identify which of the following functions are eigenfunctions of the operator d/dx: (a) eikx, (b) cos kx, (c) k, (d) kx, (e) e−ax
grigory [225]

Answer: Identify which of the following functions are eigenfunctions of the operator d/dx: (a) eikx, (b) cos kx, (c) k, (d) kx, (e) e−ax2

Step-by-step explanation: First, we going to apply the operator derivate to each item. Remember that  a function f is an eigenfunction of D if it satisfies the equation

Df=λf, where  λ is a scalar.

a) D(eikx)/dx= ik*eikx, then the function is a eigenfunction and the eingenvalue is ik.

b) D(cos kx)/dx= -ksen kx, then the funcion is not a eigenfunction.

c)  D(k)/dx=0, then the funcion is not a eigenfunction.

d)  D(kx)/dx=k, then the funcion is not a eigenfunction.

e)  D(e-ax2)/dx= -2ax*e-ax2, then the function is a eigenfunction and the eingenvalue is -2ax

7 0
4 years ago
Do u no the answer please help
Gre4nikov [31]
The answers are B) and E)

3 0
3 years ago
Read 2 more answers
A container manufacturing company was contracted to design and manufacture cylindrical cans for fruit juice. The volume of each
gtnhenbr [62]

The volume of the cylinder is the amount of fruit juice it can contain.

The relationship between the volume and the surface area is:

\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}

The given parameter is:

\mathbf{V = 0.946}

The volume of a cylinder is calculated as:

\mathbf{V = \pi r^2 h}

Make h the subject

\mathbf{h = \frac{V}{ \pi r^2}}

The surface area (A) of a cylinder is:

\mathbf{A = \pi r^2 + \pi rh}

Substitute \mathbf{h = \frac{V}{ \pi r^2}}

\mathbf{A = \pi r^2 + \pi r \times \frac{V}{\pi r^2}}

\mathbf{A = \pi r^2 + \frac{V}{r}}

Differentiate

\mathbf{A' = 2\pi r - Vr^{-2}}

Set to 0

\mathbf{2\pi r - Vr^{-2} = 0}

Rewrite as:

\mathbf{ 2\pi r = Vr^{-2}}

Multiply through by r^2

\mathbf{ 2\pi r^3 = V}

Solve for r

\mathbf{r = \sqrt[3]{\frac{V}{2\pi}}}

\mathbf{A = \pi r^2 + \frac{0.946}{r}}

So, we have:

\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}

Hence, the relationship between the volume and the surface area is:

\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}

Read more about surface areas and volumes at:

brainly.com/question/3628550

8 0
2 years ago
Read 2 more answers
Which expression are equivalent to 4m-2+(-8m)
DochEvi [55]

Answer:

combine 4m -8m to get -4m

- 4m - 2

8 0
3 years ago
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1. Miss L wants to buy a new car. If the car
Simora [160]

Answer:

6,000

Step-by-step explanation:

500x12

6 0
3 years ago
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