If the patient has to take 1 pill every 6 hours, how many pills will the patient need for 3 days?

You get number one's answer by finding to difference between 13 to 7 which Is six. so now you start at 1 and add 6 which would be 7 and would give you your answer of 7 to 1.

You get number two's answer by finding the ratio given which is 1 black square to 2 Grey squares. Since it mentions to triple it you multiply both numbers by 3. which would give you 3 to 6. You know that this is right because it is equivalent to 1/2 which was what the first ratio was.

you're welcome

4 0

3 years ago

Santiago buys milk and onions at the store.He pays a total of $25.78.He pays a total of $3.58 for the milk.He buys 6 bags of oni

True [87]

Each bag of onions costs $3.70.

<h3></h3><h3>Equations</h3>

Given that Santiago buys milk and onions at the store and he pays a total of $25.78, and he pays a total of $3.58 for the milk and he buys 6 bags of onions that each cost the same amount, to determine an equation which can be used To determine how much each bag of onions costs, the following calculation must be made:

(25.78 - 3.58) / 6 = X
22.20 / 6 = X
3.7 = X

Therefore, each bag of onions costs $3.70.

Learn more about equations in brainly.com/question/2263981

7 0

3 years ago

Graph the polygon and its image after a dilation centered at C(1,1)

Grace [21]

Now we proceed to present the graphs of the polygon and its image with the help of a graphing tool. The original polygon is highlighted in red and the image is highlighted in blue.

DIlations are defined by the follwing operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation.
$k$ - Dilation factor.
$P(x,y)$ - Original point of the polygon.
$P'(x,y)$ - Dilated point of the polygon.

If we know that $O(x,y) = (1,1)$ , $k = 0.5$ , $J(x,y) = (3,1)$ , $K(x,y) = (5, -3)$ , $L(x,y) = (5,5)$ and $M(x,y) = (3,7)$ , then the coordinates of the new polygon are:

$J'(x,y) = (1,1) + 0.5\cdot [(3,1)-(1,1)]$

$J'(x,y) = (1,1)+0.5\cdot (2,0)$

$J'(x,y) = (1,1) +(1,0)$

$J'(x,y) = (2,1)$

$K'(x,y) = (1,1) + 0.5\cdot [(5,-3)-(1,1)]$

$K'(x,y) = (1,1) +0.5\cdot (4,-4)$

$K'(x,y) = (1,1) +(2,-2)$

$K'(x,y) = (3,-1)$

$L'(x,y) = (1,1) + 0.5\cdot [(5,5)-(1,1)]$

$L'(x,y) = (1,1) + 0.5\cdot (4,4)$

$L'(x,y) = (1,1) + (2,2)$

$L'(x,y) = (3,3)$

$M'(x,y) = (1,1) + 0.5\cdot [(3,7)-(1,1)]$

$M'(x,y) = (1,1) +0.5\cdot (2,6)$

$M'(x,y) = (1,1) +(1,3)$

$M'(x,y) = (2,4)$

Now we proceed to present the graphs of the polygon and its image with the help of a graphing tool. The original polygon is highlighted in red and the image is highlighted in blue.

We kindly invite to check this question on dilations: brainly.com/question/13176891

6 0

3 years ago