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1 year ago

DASAROLLA:a) (x+3) (x+5)=b) (x+4) (x-5)=

Mathematics

1 answer:

Nat2105 [25]1 year ago

8 0

Answer:

a) $x^{2}$ +8x+15

b) $x^{2}$ -x-20

Step-by-step explanation:

a) (x+3)(x+5)

a) $x^{2}$ +5x+3x+15

a) $x^{2}$ +8x+15

b) (x+4)(x-5)

b) $x^{2}$ -5x+4x-20

b) $x^{2}$ -x-20

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There are infinite numbers of rational number between any 2 rational numbers which one of the following lies between 20/30 and 4

miv72 [106K]

Answer: B 11/15

Step-by-step explanation: 11/15 = 22/30> 20/30

but 11/15 = 110 /150 < 120/150 = 30/50

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2 years ago

What is the next number in the sequence 3, 12, 24, 33, 66

ExtremeBDS [4]

75.
Explanation: from 3 to 12, you add 9, and then double the 12 to get to 24, and then add 9 again to get to 33, and double it to get 66, so the pattern is to add 9 and then double.

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2 years ago

Read 2 more answers

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

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2 years ago

10. If possible, determine whether or not triangles LQP and LMN

natita [175]

Answer:

They are similar

Step-by-step explanation:

If two triangles are similar, the ratio of their corresponding side lengths must be equal to each other.

This means that for ∆LQP and ∆LMN to be considered similar to each other, therefore:

LM/LQ = LN/LP

LM = 100

LQ = 12

LN = 75

LP = 9

LM/LQ = 100/12 = 25/3

LN/LP = 75/9 = 25/3

LM/LQ = LN/LP = 25/3, therefore ∆LQP and ∆LMN are similar to each other because the ratio of their corresponding side lengths are the same.

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2 years ago

-3 (1/-3)=1 <br>What property is this?^

Komok [63]

The inverse property of multiplication

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2 years ago

DASAROLLA:a) (x+3) (x+5)=b) (x+4) (x-5)=​

DASAROLLA:a) (x+3) (x+5)=b) (x+4) (x-5)=