Find an equation for the line through (-6, 3) and parallel to y = 3x + 1.
1 answer:
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Answer:
Graph by first drawing a horizontal line at 3 on the y axis. Anything below this line falls into the y is less than or equal to 3 range. Draw a vertical line at negative 2 on the x axis. This represents x > -2. The next one is a slanted line, so it'll be trickier to graph. If using a graph of 10 - 10, graph from (-8, -10) to (10, 8). If using a graph of 20 - 20, graph from (-18, -20) to (20, 18). As seen in the graph, anything to the upper left of this line is included.
The true inclusion is where all the ranges intersect. Be sure to color this the darkest or with a special pattern.
Answer:
Perimeter of the parallelogram = 26.64 units
Step-by-step explanation:
The perimeter of parallelogram = 2(a + b)
Here a = KJ = 7 units.
b = HK
We need to find the HK using the distance formula.
Distance formula =
H = (-4, 3) and k = (-2, -3)
Now plug in x1 = -4, y1 =3, x2 = -2, y2 = -3 in the distance formula
HK =
=
=
=
HK = b = 6.32 units
Now plug in a = 7 and b = 6.32 in the perimeter formula, we get
Perimeter = 2(7 + 6.32)
= 2(13.32)
= 26.64 units
Thank you.