Answer:

Step-by-step explanation:
Given expression is
.
Now we need to find the cube root of given expression
.
![\sqrt[3]{27a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D)
![=\sqrt[3]{3*3*3a^{4*3}}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%2A3%2A3a%5E%7B4%2A3%7D%7D)
![=\sqrt[3]{3^3\left(a^4\right)^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%5E3%5Cleft%28a%5E4%5Cright%29%5E3%7D)
![=\sqrt[3]{\left(3a^4\right)^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B%5Cleft%283a%5E4%5Cright%29%5E3%7D)
Since cube root and cube are opposite operations of each other. So they will cancel each other.

Hence correct choice is the last choice
.
<span>Answer:
First step is to find out what your x values are. The length of the interval from 2 to 14 is 12. Divide it into six equal parts, which is 2. Then the x points for the left endpoints are: 2, 4, 6, 8, 10, 12 (and the last rectangle goes from 12 to 14), but you don't use 14 unless you are doing right endpoints or trapezoids or something.)
Next step is to find the areas of the rectangles. It is just the base times the height, and the height is the function value of the x value, since the rectangle sits on the x axis and extends vertically up or down to the graph of the function. In integrals an area below the axis is considered to contribute a negative quantity to the integral, so we will do the same for rectangles that extend below the x axis.
f(2) = 3 - (1/2) 2 = 3 - 1 = 2
f(4) = 3 - 4/2 = 1
f(6) = 3 - 6/2 = 0
f(8) = 3 - 8/2 = -1
f(10) = 3 - 10/2 = -2
f(12) = 3 - 12/2 = -3
That should be in a table. Next to it you write the area, multiplied by -1 if f(x) < 0 (I'm saying that because areas are always positive.)
That gives 4, 2, 0, -2, -4, -6 for the six rectangles. Add all that up and it mostly cancels but you get -6 for the final answer.
I have explained as I went along. You do not have to explain so much when you give the answer on a test or homework. Just the computations and not so many words.</span>
I’m going to try to answer these to the best of my ability.
1. Plane D
2. Plane C
3. AB
4. No
5. I don’t believe so because it doesn’t look like C is on the same plane as a AB and D.
6. I think so, yes! Collinear means that they are on the same line, and it looks like if you put a line between those two to connect them, they would connect perfectly!
7. B possibly? Because it looks like B, C, and D are all collinear and that they would pass through a straight line. A doesn’t look like it’s collinear with the rest of them.
8. No
9. Yes
10. Yes
I’m sorry if any of those are wrong, but I did make sure to try and put some explanations for some of them so you saw why I gave the answer that I gave! I hope that helped and like I said, I’m sorry if any of them are wrong, I tried my best!
Answer:
f(x)=4784
f(13)= 0 because there is x value on the right hand side
Answer:
Number of students van can carry = 11
Number of students bus can carry = 41
Step-by-step explanation:
Given the following :
HIGH SCHOOL A:
Number of students = 184
Number of vans(v) = 13
Number of buses(b) = 1
Mathematically,
13v + 1b = 184 - - - - (1)
HIGH SCHOOL B:
Number of students = 520
Number of vans(v) = 10
Number of buses(b) = 10
Mathematically,
10v + 10b = 520 - - - - (2)
Multiply (1) by 10 and (2) by 1
130v + 10b = 1840 - - - (3)
10v + 10b = 520 - - - (4)
Subtract (4) from (3)
120v = 1320
v = 11
Substitute v = 11 into (1)
13(11) + 1b = 184
143 + b = 184
b = 184 - 143
b = 41
Number of students van can carry = 11
Number of students bus can carry = 41