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3 years ago

Find f(-3) if f(x)=X+ 2x - 1

2 answers:

4 0

Answer: f(-3)=-10
Explanation: We are given f(x)=X+2x-1. You would replace every x variable with -3. You’re new equation would look like this: f(-3)=-3+2(-3)-1. Then solve: f(-3)=-3+2(-3)-1
f(-3)= 3-6-1
f(-3)= -10

Alisiya [41]3 years ago

3 0

Answer:

i 100% do not know

Step-by-step explanation:

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

I will try to give as many details as possible.

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

Mark is going to an awards dinner and wants to dress appropriately. He had one blue shirt, one white dress shirt, one black dres

lidiya [134]

Answer:

All the four statements are true , which are -

(A) The subset contains contains of all the outfits that have grey slacks .

(B) The subset contains contains of all the outfits that have grey slacks and red tie .

(C) The subset contains contains of all the outfits that have grey slacks and blue shirt .

(D) The subset contains contains of all the outfits that do not have black slacks .

Step-by-step explanation:

We are given with Outfit 2 , 4 and 6

Outfit 2 - Blue grey red

Outfit 4 - White grey red

Outfit 6 - Black grey red

(A) Since only 2,4, and 6 contain grey slacks, and no other outfit contains grey slacks, those are the subsets that contain grey slacks. Thus , this statement is true .

(B) Just outfits 2, 4, and 6 have grey slacks and a red tie, proving the statement. Other clothes do not include grey slacks and a red tie; they may include a red tie but not both grey slacks and a red tie. Hence , the statement is true .

(C) Since the outfit 2 has grey slacks and a blue shirt, the statement is correct; no other outfit has both grey slacks and a blue shirt. Therefore , this statement is also correct .

(D) The argument is correct since all of the subsets contain grey slacks and no black slacks.

Hence , all the options A , B , C , D are correct and describes the subset .

The given question is incomplete , the complete question is attached here -

3 0

3 years ago

Which of the following shows the correct steps in solving the equation? -8x + 3 = 19

Firlakuza [10]

Answer:

-8x=19-3

-8x=16

x= 16/-8

x=-2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

⭐️ Cant figure this out?!

Natali [406]

The Answer to your question ∑ (2k -10) from 3 to k=6 is -4

8 0

4 years ago

What are the solutions of the system?

bearhunter [10]

D : no solution

Hope this works

5 0

3 years ago

Find f(-3) if f(x)=X+ 2x - 1​

Find f(-3) if f(x)=X+ 2x - 1