The height of the triangle is 19.596 centimeter, if a right isosceles triangle has an area of 192 square centimeters.
Step-by-step explanation:
The given is,
Area of right isosceles triangle is 192 square centimeters
Step:1
Formula for area of right isosceles triangle is,
............................(1)
Where, a - Sides of triangle
a = h = b
Here, h - Height of triangle
b - Base of triangle
From given,
Area, A = 192 square centimeters
Equation (1) becomes.


= 384

Take square root on both sides,

a = 19.596 centimeters
Height of right isosceles of triangle, a = h = 19.596 centimeters
Result:
The height of the triangle is 19.596 centimeter, if a right isosceles triangle has an area of 192 square centimeters.
8x² - 2x - 1 = 0
8x² - 4x + 2x - 1 = 0
4x (2x - 1) + 1 (2x - 1) = 0
(4x + 1)(2x - 1) = 0
4x + 1 = 0 or 2x - 1 = 0
x = -1/4 0r x = 1/2
Answer:
132 minutes
Step-by-step explanation:
If you see that 1 mile is 22 minutes, then you would know 2 miles is double, three miles is triple and so on. So you would do 22x6 for the six miles to get your answer of 132, or you can even do 22 plus 22 six times.
Answer:
m∠3 = 49°
Step-by-step explanation:
From the picture attached,
lines m and n are the parallel lines and line t is a transversal line intersecting these parallel lines at E and B respectively.
Therefore, ∠DEF ≅ ∠ABC [Exterior alternate angles]
m∠1 + m∠2 = m∠4 + m∠5
m∠4 = m∠5 [line s bisects ∠ABC]
50° + 48° = m∠4 + m∠4
98° = 2m∠4
m∠4 = 49°
Since, ∠4 ≅ ∠3 [Vertically opposite angles]
m∠3 = 49°