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3 years ago

What is a solution I forgot the inequality M > 13/6

Mathematics

1 answer:

o-na [289]3 years ago

7 0

The solution can be anything bigger than 13/6.

For example: 3, 4, 5, 6...ect

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Triangle ABC is a right triangle and sin(53o) = StartFraction 4 Over x EndFraction. Solve for x and round to the nearest whole n

zmey [24]

Answer:

cos(53°)=StartFraction y Over 5 EndFraction

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of x

we know that

$sin(53\°)=\frac{4}{x}$

Solve for x

$x=\frac{4}{sin(53\°)}$

$x=5$

step 2

Find the cosine of angle A

The cosine of angle A is equal to divide the adjacent side to angle A (AC) by the hypotenuse (AB)

$cos(53\°)=\frac{y}{x}$

substitute the value of x

$cos(53\°)=\frac{y}{5}$

cos(53°)=StartFraction y Over 5 EndFraction

4 0

4 years ago

Solve for x x^2 + 6x + 1 = 0

anygoal [31]

Answer:

x = -.1715 ≈ - .172 or x = -5.83

Step-by-step explanation:

x² + 6x + 1 = 0

x² + 6x = -1

Complete the square Add to both sides (1/2 of the x-term, then square it.)

x² + 6x + 9 = -1 + 9

(x + 3)(x + 3) = 8

(x + 3)² = 8

$\sqrt{(x + 3)^{2}$ = $\sqrt{8}$

x + 3 = ± $\sqrt{8}$

x = -3 ± $\sqrt{8}$

x = -3 + $\sqrt{8}$ or x = -3 - $\sqrt{8}$

x = -.1715 ≈ - .172 or x = -5.83

6 0

3 years ago

According to the article "Fatigue Testing of Condoms" (Polymer Testing, 2009: 567–571), "tests currently used for condoms are su

daser333 [38]

Answer:

99% Confidence interval: (1196,1973)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 20

Mean, μ = 1584

Standard Deviation, σ = 607

99% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.01} = \pm 2.86$

$1584 \pm 2.86(\dfrac{607}{\sqrt{20}} )\\\\ = 1584 \pm 388.18\\ = (1195.82 ,1972.18)\\ \approx (1196,1973)$

Thus, there is a 99% chance that it will break in approximately 1196 to 1972

6 0

3 years ago

In a number with at least two digits, the last number was removed. The resulting number was n smaller than ghe previous one.

BartSMP [9]

Answer:

The largest possible value of n is 11.

(A) is correct option.

Step-by-step explanation:

Given that,

The number with at least two digits,the last number was removed. The resulting number was n smaller than the previous one.

We need to find the largest possible value of n

Using given data,

The smallest number of two digit is 10.

Now, we removed last digit then we get 1 which is equal to 10 divided 10.

So, n = 10

But the largest number of two digit is 99.

We removed last digit then we get 9 which is equal to 99 divided 11.

So, n = 11

Hence, The largest possible value of n is 11.

(A) is correct option.

5 0

3 years ago

Which solid has a triangle as its side view and a triangle as a cross section perpendicular to its base?

Ugo [173]

Answer:

Step-by-step explanation:

No explaintion sorry.

Hope this helps!

5 0

2 years ago