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iogann1982 [59]
3 years ago
9

If "i" is raised to an odd power, then it cannot simplify to be a)-1 b)-i c)i

Mathematics
2 answers:
3241004551 [841]3 years ago
6 0
i ^1 = i
i ^ 2 = - 1
i ^ 3 = - i
i ^4 = 1
etc.
................
"i" raised to an odd power cannot simplify to be : A ) - 1
shutvik [7]3 years ago
6 0

Answer:

Hence, option A is correct.

Step-by-step explanation:

'i' is a complex number with the property that:

i^2=-1\\\\i^3=-i\\\\i^4=1\\\\i^5=i

and the terms will continue so on.

if i is raised to an odd power then we will never get '-1' term.

Because every even power of i will be either '1' or '-1' and so the next power of the even power will be odd and hence '1' or '-1' will get multiplied by i and hence lead to the term either 'i' or '-i'.

Hence If "i" is raised to an odd power, then it cannot simplify to be '-1'.

Hence, option A is correct.



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The solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

y=6x-3\\y=x-2

Solving:

Let:

y=6x-3--eq(1)\\y=x-2--eq(2)

Put value of y from equation 2 into equation 1

y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}

Now, put value of x in equation 2 to find value of y

y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}

So, the solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

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