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3 years ago

If "i" is raised to an odd power, then it cannot simplify to be a)-1 b)-i c)i

2 answers:

6 0

i ^1 = i
i ^ 2 = - 1
i ^ 3 = - i
i ^4 = 1
etc.
................
"i" raised to an odd power cannot simplify to be : A ) - 1

shutvik [7]3 years ago

6 0

Answer:

Hence, option A is correct.

Step-by-step explanation:

'i' is a complex number with the property that:

$i^2=-1\\\\i^3=-i\\\\i^4=1\\\\i^5=i$

and the terms will continue so on.

if i is raised to an odd power then we will never get '-1' term.

Because every even power of i will be either '1' or '-1' and so the next power of the even power will be odd and hence '1' or '-1' will get multiplied by i and hence lead to the term either 'i' or '-i'.

Hence If "i" is raised to an odd power, then it cannot simplify to be '-1'.

Hence, option A is correct.

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A car travels 3 times around a traffic circle whose radius is 80 feet. What is the distance the car will travel? Use 3.14 for π

Harman [31]

Answer : Distance will be 1507.2 feet .

Explanation :

Since we have given that

Radius of circle = 80 feet

So,

Circumference of circle is given by

$2\pi r=2\times 3.14\times 80=502.4 \text{ feet}$

Since , a car travels 3 times around a traffic circle.

So,

$\text{ Distance covered by the car will travel}= 3\times 502.4= 1507.2 \text{ feet }$

So, Distance will be 1507.2 feet .

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2 years ago

the measure of the seven angels in an octagon measure 129, 132, 136, 124, 141, 158, and 116. what is the measurement of the last

Taya2010 [7]

Answer:

116

Step-by-step explanation:

IT SAYS WHAT IS THE MEASUREMENT OF THE LAST ANGLE 116 WHAT THE LAST NUMBER.

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2 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

2 years ago

Find the volume of a rectangle box 12cm by 15cm by 10cm

olga nikolaevna [1]

Answer:

Step-by-step explanation: