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3 years ago

The sum of 10 and hans savings is 49. Use the variable h to represent Hans savings.

Mathematics

1 answer:

andrey2020 [161]3 years ago

7 0

Answer:

39 I believe. The question is a little confusing.

Step-by-step explanation:

49-10=h 39=h

Not sure if this is what you want the question is worded weirdly.

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Can 6 fit into 36 and if so how many times

ratelena [41]

Yes.
This is the same thing as:
$\frac{36}{6} =6$

How many times can 6 go into 36?
6 times
Try:
6*6=36

So true.

Hope this helps! :D

6 0

3 years ago

Read 2 more answers

(Can somebody find the sum of this) (5+2i)+(8-3i)

7nadin3 [17]

Hey there!!

Okay so here are the steps....

(5 + 2i) + (8 - 3i) <---- when we have exponents we should worry about the "i" because it is equal to √-1 but here it isn't the case.


(13 - i) <----- This is the answer!

I hope this helps! ^__^

7 0

3 years ago

Shen ran for president of the chess club, and he received 14 votes. There were 35 members in the club. What percentage of the cl

RUDIKE [14]

Answer:

40%

Step-by-step explanation:

14/35 members voted him. Lets convert this into a percentage:

14/35 * 100% = 14/35 *100/100 = 40%

I hope this helps! :)

3 0

3 years ago

Help will give Brainliest

ryzh [129]

Multiply the price by (1 + sales tax).

85 x (1+0.07)

85 x 1.07 = 90.95

He will pay $90.95

4 0

3 years ago

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I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

3 years ago