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Luden [163]
3 years ago
15

A super train traveled 420 miles in 3 hours. If it maintain the same speed, how far could the train travel in 16 hours?

Mathematics
1 answer:
Readme [11.4K]3 years ago
8 0

Answer:

We conclude that the train can travel 2240 miles in 16 hours.

Step-by-step explanation:

Given that a  super train traveled 420 miles in 3 hours.

  • Distance covered = 420 miles
  • Time taken = 3 hours

Step 1 of 2

Determine distance per hour

<u>Important Tip:</u>

  • The distance per hour can be determined by dividing the distance covered by the time taken.

Distance per hour = Distance Covered / Time taken

              = 420 / 3

              = 140 miles per hour

Step 2 of 2

Determine the distance traveled in 16 hours

We already know that a super train travels 140 miles per hour. In other words, the speed of the super train is 140 miles per hour.

<u>Important Tip:</u>

  • To determine the distance covered in 16 hours, all we need to do is to multiply the distance covered per hour i.e. 140 with the total number of hours i.e. 16.

Distance traveled in 16 hours = Distance per hour × 16

                                                 =  140 × 16

                                                 = 2240 miles

Conclusion:

Therefore, we conclude that the train can travel 2240 miles in 16 hours.

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Step-by-step explanation:

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2 years ago
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P(X&lt; ) 1-P(X&gt; ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
3 years ago
5x - (x + 3)= 1/3 (9x + 18) - 5
telo118 [61]
1/3(9x) =3x
1/3(18) =6

3x+6-5

Then you do
-(x)=-x
-(3)=-3

5x-x-3 = 4x-3

4x-3=3x+6-5
4x-3=3x+1

x=4
4 0
3 years ago
Read 2 more answers
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