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krek1111 [17]
3 years ago
7

Solve using proportions.

Mathematics
1 answer:
denis23 [38]3 years ago
3 0

Answer:

7.8 = k

Step-by-step explanation:

Since the figures are similar, we can use proportions

c           k

----- = -------

b            j

Substituting the values in

6.5         k

----- = -------

4          4.8

Using cross products

6.5 * 4.8 = 4k

31.2 = 4k

Divide each side by 4

31.2/4 = 4k/4

7.8 = k

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Answer:

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There are more than one answer help me and I give brainilest
andreev551 [17]

Answer:

Equivalent to a), b), and d). It is NOT equivalent to c).

Step-by-step explanation:

6m + 12 is also equivalent to a) 3(2m+4) because when you distribute, it's 6m + 12. It is also equivalent to b) 3m + 8 + 4 + 3m because if you add them together, you get 6m + 12. It is not equivalent to c) but is do d) 4m + 2(m + 6) cause you use the distributive property then add. I hope this helped and please mark brainliest!

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3 years ago
What is x - 5y = 13 and 9y - x = -17 using elimination method
Genrish500 [490]
X +(-5y)=  13
-x+  9y =(-17)
0+<u>4y</u>=<u>-4</u>
    4    4
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6 0
3 years ago
Suppose that y varies directly with x and inversely with z and y = 28 when x = 32 and z = 8. write the quation that models the r
WITCHER [35]
Given that y varies directly with x and inversely with z, then:
a] Equation that models the relationship
y=kx/z
where k is the constant of proportionality, given by:
k=yz/x
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k=7
The equation that models the relationship is:
y=7x/z


b] 
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</span>
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3 years ago
SHOE COLLECTION: Marquise, Bron'Tavious, and JayDarius each have a shoe collection of Nike Air Vapor Max shoes. Marquise has two
Natasha_Volkova [10]

Answer:

(a) The number of shoes that Marquise has is 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has is 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has is 35 pairs of shoes

Step-by-step explanation:

The given information are;

The number of shoes that Marquise has = 2 × The number of pairs of shoes that Bron'Tavious

The number of pairs of shoes that JayDarius has = The number of pairs of shoes that Bron'Tavious + 15

The total number of pairs of shoes they have all together = 95 pairs of shoes

Let the number of pairs of shoes that Bron'Tavious has = X. Therefore, we have;

The number of shoes that Marquise has = 2 × X

The number of pairs of shoes that JayDarius has = X + 15

The total number of pairs of shoes they have all together = X + X + 15 + 2 × X = 95

X + X + 15 + 2 × X = 95

4 × X + 15 = 95

4 × X = 95 - 15 = 80

X = 80/4 = 20

∴ X = 20

(a) The number of shoes that Marquise has = 2 × X = 2 × 20 = 40

The number of shoes that Marquise has = 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has = X = 20

The number of pairs of shoes that Bron'Tavious has = 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has = X + 15 = 20 + 15 = 35

The number of pairs of shoes that JayDarius has = 35 pairs of shoes.

5 0
3 years ago
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