Answer:
Graph the polynomial in order to determine the intervals over which it is increasing or decreasing. Increasing on: (1,∞) ( 1 , ∞ ). Decreasing on: (−∞,1) ( - ∞ , 1 ).
Step-by-step explanation:
You'd do the same as in
brainly.com/question/2700999lemme hmmm redo the fractions... and as I said, you flip them around as needed
notice, we flipped them some, so the unit ends either above or below
in order to cancel the one on the left
Answer:
Write the following sentences and give the function of each underlined word.
a. Yellow describes snake and crawled tells of an action.
b. Shoaib is the name of a person and large describes the company.
c. Tap is the name of a thing; yesterday tells when it was leaking (helps describe the action).
d. Me stands in place of a noun (the person speaking) and morning is the name given to the early
part of the day.
e. And joins two parts of the sentence; are fed tells of an action (continuing).
f. Saw tells of a past action; in shows the relationship between peacock and forest.
g. Oh! Shows a feeling or emotion; new describes the car.
Answer:
110011
Step-by-step explanation:
The tedious way to do this is to divide by 2 until the quotient is 0, noting remainders at each step:
- 51/2 = 25 r 1
- 25/2 = 12 r 1
- 12/2 = 6 r 0
- 6/2 = 3 r 0
- 3/2 = 1 r 1
- 1/2 = 0 r 1
Taken from bottom to top, the list of remainders comprises the binary number: 110011.
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Alternatively, you can convert the number to hexadecimal (base-16) or octal (base-8), then make the simple conversions from those digits to binary. In octal, we have ...
Then the number in octal is 51 = 63₈. Your familiarity with binary lets you write the binary number from memory, since you recall 6 = 110₂ and 3 = 011₂. Each octal digit must be expressed as three binary digits (or bits) in order to maintain appropriate place values.
That is, ...
63₈ = 110011₂
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<em>Comment on octal-binary conversion</em>
The binary values of the digits 0-7 are ...
- 0 = 000₂
- 1 = 001₂
- 2 = 010₂
- 3 = 011₂
- 4 = 110₂
- 5 = 101₂
- 6 = 110₂
- 7 = 111₂
Three binary bits can express numbers 0-7 as shown. So, using octal as an intermediate base in doing the conversion to binary lets you do the conversion 3 bits at a time, instead of one bit at a time.
Likewise, four binary bits can express numbers 0-15, so hexadecimal as an intermediate base lets you do the conversion 4 bits at a time: 51/16 = 3 r 3 ⇒ 0011 0011₂.