Slope of a line passing though point (x1,y1) nd (x2,y2) is
(y2-y1)/(x2-x1)
we have
(1,-3) and (3,-5)
x1=1
y1=-3
x2=3
y2=-5
slope=(-5-(-3))/(3-1)=(-5+3)/(2)=-2/2=-1
slope=-1
3x^2 * 4x^3 = 12x^5
Answer is degree 5
Answer:
D: x = 2
Step-by-step explanation:
Go down the multiple choices answers and plug each value in for x until the inequality is true:
A:
1/4(32) < 8
1/4 × 32/1 < 8
32/4 < 8
8 < 8
8 is not less than 8 so this is false (8 = 8).
B:
1/4(35) < 8
35/4 < 8
8 3/4 < 8
8 3/4 is not less than 8 so this is false (8 3/4 > 8).
C:
1/4(34) < 8
34/4 < 8
8 2/4 < 8
8 2/4 is not less than 8 so this is false (8 2/4 > 8).
D:
1/4(2) < 8
2/4 < 8
2/4 is less than 8 so this is true (2/4 = 1/2 = 0.5 > 8).
Answer:
Initial equation: 5x + 2 = 3x + 12
x = 5
Step-by-step explanation:
Point C is the midpoint between A and B.
This means that:
AC = CB
We have that:
AC = 5x + 2
CB = 3x + 12
Since AC = CB, the initial equation is:
5x + 2 = 3x + 12
Now we can solve
5x + 2 = 3x + 12
5x - 3x = 12 - 2
2x = 10
x = 10/2
x = 5
