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abruzzese [7]
3 years ago
15

What are the first 10 prime numbers and How

Mathematics
1 answer:
Anna [14]3 years ago
3 0
2, 3, 5, 7, 11, 13, 17, 19, 23, 29

A prime number is a number that is only divisible by 1 and itself

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If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:
Liula [17]

Answer:

(a) The mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c) The mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d) The mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean, variance and standard deviation of <em>X</em> are:

\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}

(a)

For <em>n</em> = 4 and <em>p</em> = 0.40 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98

Thus, the mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b)

For <em>n</em> = 4 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80

Thus, the mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c)

For <em>n</em> = 3 and <em>p</em> = 0.50 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87

Thus, the mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d)

For <em>n</em> = 5 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89

Thus, the mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

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3 years ago
Dan buys candy that cost $7 per pound . he will buy at most 6 pounds of candy . What are the possible amounts he will spend on c
Komok [63]

Answer:

About $42

Step-by-step explanation:

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State the number you would multiply each side of the proportion by to isolate the variable.
MakcuM [25]

Answer:

You would multiply both sides by 6.

Step-by-step explanation:

Since they both have 6 already they would just cancel out.

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Graph a line with a slope of 2/5 that contains the point (-2 4)
Minchanka [31]

Answer:

The equation for the line is y = 2/5x + 24/5

Step-by-step explanation:

If you need the exact points, go to m4thway and plug that equation in.

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3 years ago
List all the factors of 12​
S_A_V [24]

Answer:

Step-by-step explanation:

The factors are 1 2 3 4 6 and 12

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4 years ago
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