Answer:
I don't know the exact answer because I'm 13 but does this help at all? Sorry about before...
Step-by-step explanation:
1. The domain D and range R of the given function are given by: D: (- ∞ , + ∞) and R: (- ∞ , + ∞)
2. In order to find the inverse, we first write the function as an equation as follows. ...
3. Then solve it starting by cubing both sides. ...
4. Simplify and solve for x. ...
5. Change x into y and y into x to obtain the inverse function.
Answer:
(1) . -11
Step-by-step explanation:
f(-2)=-3(-2)^2+
-12+1=-11
Answer:
6
Step-by-step explanation:
Your function is split into 4 parts.
We want to use the piece that includes x=6.
This only included in the inequality that says x is greater than or equal to 5. Since that is, we use the expression that corresponds to that to find f(6).
f(6)=2(6)-6
f(6)=12-6
f(6)=6
Answer:
1. 70.
2. 29.
3. 442.5
4. 289.
5. 632.
Step-by-step explanation:
The key to doing these is to split the polygons into rectangles, triangles or trapezoids as appropriate.
For example, number 1 consists of a rectangle area 8 * 8 and another of 3* 2.
So the area = 64 + 6 = 70 unit^2.
2. The area = sum of 3 rectangles 1*1 + 4*6 + 2*2.
3. Area = 11*15 + 11*15 + 1/2*15*15
4. Area = 18*12 + 1/2 * 6 * 15 + 1/2 * 7 * 8.
5. Area = area of 2 rectangles + area of a trapezoid.
= 18 * 24 + 4*10 + 1/2(12 + 20) * 10.
Slope (m) of a line = (y2-y1)/(x2-x1)
So for line AB, the slope is (3-2)/(-1-1)
= 1/-2 = -1/2
For line AC = (3--1)/(-1--3) = (3+1)/(3-1)
= 4/2 = 2
For line BC = (2--1)/(1--3) = (2+1)/(1+3)
= 3/4
In order for an angle (<) to be right, it must be 90°, so the two lines making the right angle must be perpendicular. Perpendicular lines by definition have slopes that are the negative reciprocal. That means that you change the sign of one line's slope (m) and divide 1 by it:
m2 = 1/-m1
So for lines AB and AC: m(AC) = 1/-m(AB),
does 2 = 1/--1/2? YES!! 1/--1/2 = 1/1/2 = 2, so < BAC is 90° and therefore a right <
How about for lines AB and BC: m(BC) = 1/-m(AB), does 3/4 = 1/--1/2? NO, because 1/--1/2 = 1/1/2 = 2, not = to 3/4, so < ABC is not right
How about our last < BCA: m(AC) = 1/-m(BC), does 2 = 1/-3/4? NO, because 1/-3/4 = -4/3, not = to 2, so < BCA is not right
So yes, the triangle is a right triangle because < BAC is right (=90°)!