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Shalnov [3]
3 years ago
12

I need help plsss idk how to do this​

Mathematics
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

(1) . -11

Step-by-step explanation:

f(-2)=-3(-2)^2+

-12+1=-11

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You need 333 sticks of butter for every 242424 cookies you bake.
kiruha [24]

Answer:

1/728

Step-by-step explanation:

333/242424 =

1/728

4 0
3 years ago
What is the common denominator of 3/5, 7/8, and 5/6?
vovangra [49]

Hello from MrBillDoesMath!

Answer:

240 is one common denominator.

(Not asked for by problem but  least common denominator is 120)

Discussion:

A common denominator (one of many) is given by multiplying the denominators: 5, 8, and 6. That is 5*8*6 = 240 is a common denominator.

If the <u>least common denominator</u> is desired, then that is 5 * 8 * 3 = 120

(we use 3 as 6 = 2*3 but 2 is already accounted for in the factorization of 8)


Thank you,

MrB

4 0
4 years ago
Read 2 more answers
3. Before tax, Louise spent a total of $38 on the items below at Starbucks
soldier1979 [14.2K]

Answer:

  47.4%

Step-by-step explanation:

The total amount Louise spent on Frappuccinos was 4×$4.50 = $18. The fraction that is of the total is ...

  Fraps/Total = $18/$38 = 9/19

That can be converted to a percentage by multiplying by 100%:

  9/19 = (9/19)×100% ≈ 47.4%

Louise spent 47.4% of the $38 on Frappuccinos.

_____

<em>Additional comment</em>

The decimal equivalent of 9/19 is a repeating decimal with an 18-digit repeat.

8 0
2 years ago
Read 2 more answers
If you treat 2 friends to lunch, the first lunch is 12.25
vivado [14]
So I am guessing your asking what ur saying is how much is all the lunches together it is 24.50
8 0
4 years ago
Read 2 more answers
The width x of your iris decreases from 4 millimeters to 2 millimeters when you enter a dark room. How many times greater is the
inysia [295]

Answer:

The area of the Iris is 4 times greater.

Step-by-step explanation:

Firstly, we have to realize that we cannot solve this problem without knowing the radius of the iris. because from the information given, the radius of the iris could well be the size of the galaxy and contract from width of 4mm to 2mm and we wouldn't know!

The average radius of the iris is 6mm, so we take this value.

Now, initially the width of the iris is 4mm, that means the radius of the pupil is:

6mm-4mm=2mm

Therefore it's area A is:

A=\pi r^2=\pi (2)^2=4\pi

When the iris contracts to 2mm, the radius of the pupil becomes:

6mm-2mm=4mm

Then it's area is A:

A=\pi r^2=\pi (4)^2=16\pi

To find how many times greater this final area is than the initial area, we just divide it by the initial area:

\frac{16\pi }{4\pi } =4

This is 4 times greater than the initial area.

3 0
4 years ago
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