Answer:
The margin of error is 6.45.
Step-by-step explanation:
The complete question is:
As an early intervention effort, a school psychologist wants to estimate the average score on the Stanford-Binet Intelligence Scale for all students with a specific type of learning disorder using a simple random sample of 36 students with the disorder.
Determine the margin of error, of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume that the standard deviation IQ score among the population of all students with the disorder is the same as the standard deviation of IQ score for the general population, σ = 15 points.
The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

The margin of error for this interval is:

Given:
<em>n</em> = 36
σ = 15
(1 - <em>α</em>)% = 99%
Compute the critical value of <em>z</em> for 99% confidence level as follows:

*Use a <em>z</em>-table.
Compute the value of MOE as follows:



Thus, the margin of error is 6.45.
7x-1+5x-23= 180
12x-24=180
12x=204
X=17
total weight of both bags = 3 oz + 20.6m oz
Don's bag = 2 oz
Jamie's bag = 1 oz
Don's marbles = 9.4 oz * m
Jamie's marlbes = 11.2 oz * m
Total weight of Don's bag = 2 oz + 9.4m oz
Total weight of Jamie's bag = 1 oz + 11.2m oz
2 oz + 9.4m oz + 1 oz + 11.2m oz = 3 oz + 20.6m oz
Answer:
i do not know but you need to answer you text messages
Step-by-step explanation:
Answer: Fraction of paint used for bird house = 
Step-by-step explanation:
Let quantity of the total paint be 1.
Given: Fraction of paint to book shelf = 
Fraction of Paint to leg = 
Fraction of Paint left = 
Let x= fraction of paint used for bird house.
Total paint = 

So, Fraction of paint used for bird house = 