The angle bisector of ∠ACD in rhombus ABCD makes a 64° angle with the diagonal

Mathematics

1 answer:

True [87]3 years ago

3 0

Answer:

104°

Step-by-step explanation:

Even a crude diagram can be helpful. Half of angle ACD is the complement of the 64° angle made with diagonal BD. Since that complement, 26°, is half the bisected angle, which is half the measure of ∠BAD, the measure of ∠BAD must be 4×26° = 104°.

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Opposite angles of a rhombus are congruent, and each diagonal is a bisector of the angles at its endpoints. The diagonals bisect each other and meet at right angles.

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So x will be 12.

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