The angle bisector of ∠ACD in rhombus ABCD makes a 64° angle with the diagonal
1 answer:
Answer:
104°
Step-by-step explanation:
Even a crude diagram can be helpful. Half of angle ACD is the complement of the 64° angle made with diagonal BD. Since that complement, 26°, is half the bisected angle, which is half the measure of ∠BAD, the measure of ∠BAD must be 4×26° = 104°.
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Opposite angles of a rhombus are congruent, and each diagonal is a bisector of the angles at its endpoints. The diagonals bisect each other and meet at right angles.
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Answer:
ok, so pretty much you can set up an equation for this. You can use fractions to find this out.
Step-by-step explanation:
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