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fenix001 [56]
3 years ago
11

How many sides does a polygon have if each of its interior angle is 120

Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0
There are six sides
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Write at least four rational numbers between -2/5 and -1/3.​
castortr0y [4]
Answer: -3/5, -1/2, -7/12, -6/11
7 0
3 years ago
Read 2 more answers
The equation x ^ 2 - 2x + y ^ 2 - 4y = 20 defines a circle in the xy-coordinate plane What is the radius of the circle?
Helga [31]

Answer:

I'll set up the problem and you can do the calculation

Step-by-step explanation:

we need to complete the squares to get the equation in the general form:

{(x - h)}^{2}  +  {(y - k) }^{2}  =  {r}^{2}

where h = the x coordinate of the center

k = the y coordinate of the center

r = the radius

so looking at

{x}^{2}  - 2x

we can see that if use -1 as the constant we have

{(x - 1)}^{2}  =  {x}^{2}  - 2x   + 1

doing the same for y

{y}^{2}  - 4y

we can use -2 as the constant (basically you that the s

quare of the y coefficient )

{(y - 2)}^{2}  =  {y}^{2}  - 4y   + 4

so now we have to add or subtract the constant on the RHS to see what the square of the radius is according to the general form of the equation at the top

20 +1+4=25

Take the square root and you have the radius

4 0
3 years ago
Pls help me
gizmo_the_mogwai [7]

Answer:

no

no

no

yes yes

Step-by-step explanation:

not 100% but it should be right

3 0
3 years ago
PLEASE HELP 100 POINTS!!! The function f(x)=12sin(x−π4) is used to describe a water wave. The value x is the time in seconds, an
Otrada [13]

Answer:

okay, y=(1)/(2)*\sin (x-(\pi )/(4))

Step-by-step explanation:

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6 0
3 years ago
Determine whether the integral is convergent or divergent. ∫[infinity] 2 e^−1/x / x^2 dx : O Convergent O divergent If it is con
monitta

Let f(x)=e^{-1/x}. Then f'(x)=\frac1{x^2}e^{-1/x}>0 for all x\ge2, so f is strictly increasing. As x\to\infty, e^{-1/x}\to e^0=1, so f is bounded above by 1. This is to say,

e^{-1/x}

and the integral of \frac1{x^2} converges over the same domain, so this integral must also converge by comparison.

We have, by setting y=-\frac1x,

\displaystyle\int_2^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx=\int_{-1/2}^0e^y\,\mathrm dy=e^0-e^{-1/2}=1-\frac1{\sqrt e}

8 0
3 years ago
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