Twice the difference of two numbers is 14 and their sum is 3
find the numbers.
2 answers:
Let, x+y = 3
2(x-y) = 14
Substitute value from eq (1) in eq (2),
2(3-y-y) = 14
2(3-2y) = 14
6-4y = 14
-4y = 8
y = -2
Put it into eq (1),
x-2 = 3
x = 5
So, x = 5 & y = -2
Hope this helps!
They are 5 and minus 2
You have to solve the system of equations
2(a-b)=14
a+b=3
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