Answer:
n + 14
I don't know if it's correct but i'm trying to help :)
Y = 3/5x + b
3 = 3/5(-1) + b
3 = -3/5 + b, b = 3 3/5
Y = 3/5x + 3 3/5
Could 10.6\text{ cm}, 5.6\text{ cm},10.6 cm,5.6 cm,10, point, 6, space, c, m, comma, 5, point, 6, space, c, m, comma and 4.0\tex
vladimir1956 [14]
Since we know that triangle inequality theorem states that sum of any two sides of a triangle must be greater than third side.
Now let us see if it is true for our given side lengths.
Now let us try with another pair.
We can see that sum of 5.6 and 4 is less than 10.6. Therefore, 10.6 cm, 5.6 cm and 4.0 cm can not be side lengths of a triangle.
Answer:
Step-by-step explanation:
First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items
F(x) = x^3-3x^2+0x+0
We have to divide this by x-2
Leading terms in the dividend and divisor are
x^3 and x
Hence quotient I term would be x^3/x=x^2
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
Multiply x-2 by x square and write below the term and subtract
We get
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
---------------
-x^2+0x
Again take the leading terms and find quotient is –x
x-2) x^3-3x^2+0x+0(x^2-x
x^3-2x^2
---------------
-x^2+0x
-x^2-2x
Subtract to get 2x +0 as remainder.
x-2) x^3-3x^2+0x+0(x^2-x-2
x^3-2x^2
---------------
-x^2+0x
-x^2+2x
-------------
-2x-0
-2x+4
------------------
-4
Thus remainder is -4 and quotient is x^2-x-2
Hello!
To find the interquartile range you subtract the lower quartile by the higher quartile
33 - 25 = 8
The answer is C)8
Hope this helps!
