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Natasha2012 [34]
3 years ago
12

Select all relations that represent functions.

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

FIRST OPTION.

SECOND OPTION.

FOURTH OPTION.

Step-by-step explanation:

By definition, a relation is a function if an only if each input value ( each x- value) has only one output value (y-value).

Based on this you can identify that:

1. The relation (8,7), (7,8), (6,5), (5,6)  is a function.

2. The relation (-2,7), (-3,9), (-5,9), (-8,11) is a function.

3. The relation (6,-6), (-3,12), (6,-1), (-8,13) is not a function, because the input value 6 has two different output values:

x=6,y=-6\\\\x=6,y=-1

4. The first table represents a function.

5. The second table does not represent a function, because the input value 0 has two different output values:

x=0,y=0.5\\\\x=0,y=2

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Hello from MrBillDoesMath!

Answer:

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4x^2 + 12x + 9 =                => factor "4" from first 2 terms

4 (x^2 + 3x) + 9 =               => complete the square, add\subtract (1.5)^2

4(x^2 + 3x + (1.5)^2)  - 4 (1.5)^2 + 9  =

4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) =           => as (1.5)^2 = 2.25

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