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Nady [450]
3 years ago
11

How many nucleotides are shown in the structure you just built?​

Biology
1 answer:
ICE Princess25 [194]3 years ago
5 0

Answer:

More than 5

Explanation:

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What is a type of emigration where offspring move<br> away from their parents.
Bas_tet [7]

Answer:Dispersal

Explanation: This refers to offspring moving away from their parents. This prevents the offspring from competing with the parents for resources such as light or water. For example, dandelion seeds have “parachutes.” They allow the wind to carry the seeds far from the parents

5 0
3 years ago
2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

3 0
3 years ago
Which of the following could be a function of a phagocyte?
11Alexandr11 [23.1K]

D. Producir anticuerpos específicos para un patógeno

5 0
3 years ago
Human papillomavirus (HPV) is a double-stranded DNA virus that enters the cytoplasm before undergoing uncoating. Although the vi
Roman55 [17]

Answer:

Basal cells, keratinocyte

Explanation:

The viral DNA replication is inhibited until<u> Basal cells</u>  are differentiated into <u>keratinocyte</u>, which are ready to be shed from the epithelial layer, increasing the likelihood that HPV will be transmitted to a new host.

95% of the cells in the epidermis are keratinocytes

Basal cells are multipotent stem cells that are important in the regeneration of homeostasis of the respiratory epithelial cell population.

in skin growth, most of the cells are keratinocytes and they are formed by the division of stem cells in the basal layer

6 0
3 years ago
what differences do you observe in the syringe or its contents before the air was pumping into the syringe and after?
Kaylis [27]

Answer:

what differences do you observe in the syringe or its contents before the air was pumping into the syringe and after?

Explanation:

When an air bubble enters a vein, it's called a venous air embolism. When an air bubble enters an artery, it's called an arterial air embolism. These air bubbles can travel to your brain, heart, or lungs and cause a heart attack, stroke, or respiratory failure.You can compress it, or squeeze it into a smaller volume. When you push on the plunger you can feel the air pushing back. When you stop pushing, the air inside the syringe will return to its original size.

6 0
3 years ago
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