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Fynjy0 [20]
3 years ago
8

Serena is adding headers and footers in the Slide Master view using the Header and Footer dialog box What is not

Computers and Technology
2 answers:
nalin [4]3 years ago
7 0

Answer:

company Logo

Explanation:

sergiy2304 [10]3 years ago
5 0

Answer:

NUMBER 3

Explanation:

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Which of the statements below is true?
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<h3>Which statement is true of microsoft word?</h3>

In Microsoft word, there are different toolbars that are useful in operation. Now, from the given image from Microsoft word, we can see that toolbar is clicked. However in the fly-down from it, we see that the standard, formatting and drawing toolbars are ticked and as such they are the ones displayed.

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Read more about a true statement at; brainly.com/question/25605883

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2 years ago
How many cost units are spent in the entire process of performing 40 consecutive append operations on an empty array which start
Alexus [3.1K]

Answer:

Explanation:

260 cost units, Big O(n) complexity for a push

6 0
2 years ago
Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
Gnesinka [82]
JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
7 0
3 years ago
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