Answer:
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The given statement that is true is; B: The Formatting, Standard, and Drawing toolbars are displayed.
<h3>Which statement is true of microsoft word?</h3>
In Microsoft word, there are different toolbars that are useful in operation. Now, from the given image from Microsoft word, we can see that toolbar is clicked. However in the fly-down from it, we see that the standard, formatting and drawing toolbars are ticked and as such they are the ones displayed.
Looking at the options, the correct one is Option B because it tells us that Formatting, Standard, and Drawing toolbars are displayed.
Read more about a true statement at; brainly.com/question/25605883
Answer:
Explanation:
260 cost units, Big O(n) complexity for a push
JAVA programming was employed...
What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules
Solution:
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:
x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement