Y’all just asking for people do your work, literally not even a question
Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt =
but k = 0, therefore Probability that there is success on the first attempt = 
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = ![[1-e^{-G}]^k=[1-0.135]^k=0.865^k](https://tex.z-dn.net/?f=%5B1-e%5E%7B-G%7D%5D%5Ek%3D%5B1-0.135%5D%5Ek%3D0.865%5Ek)
P(success in k+1 attempt) = 
Probability of exactly k collisions and then a success = 
c) Expected number of transmission attempts needed = probability of success in k transmission = 
Answer:
let cookieNumber = Math.floor(Math.random() * 10)
switch (cookieNumber) {
case 1:
document.write('Fortune 1')
break;
case 2:
document.write('Fortune 2')
break;
case 3:
document.write('Fortune 3')
break;
case 4:
document.write('Fortune 4')
break;
case 5:
document.write('Fortune 5')
break;
case 6:
document.write('Fortune 6')
break;
case 7:
document.write('Fortune 7')
break;
case 8:
document.write('Fortune 8')
break;
case 9:
document.write('Fortune 9')
break;
case 10:
document.write('Fortune 10')
Explanation:
The cookieNumber is generated using Math.random(), which is rounded to a whole number using Math.floor(). Then, a switch block is used to display a different fortune depending on the value of cookieNumber.
Answer:
B And A
Explanation:
B: The controller renders a responce it can be seen as a manager and other parts are its workers and makes sure that other parts are "working" well