Answer:
dh/dt = 3/25π m/min
Step-by-step explanation:
Radius = 5m
Rate (dV/dt) = 3 cm^3 / min
Leaking rate = 1 cm^3 / min
Volume = πr^2h
Volume = π(5)^2h
V= 25πh
Differentiate volume implicitly with respect to time
dV/dt = 3 cm^3/min
3 = 25π(dh/dt)
dh/dt = 3 m^3/min /25πm^2
dh/dt = 3/25πm/min
I’m also still at finding answer so keep calm and I will give answer
its X < 1 or x > 3
where every the point goes is where the graph goes is what I do
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