Answer:
Step-by-step explanation:
is the least steeped graph
- The greater the slope, the steeper the line.
- Also you use the absolute values of the slopes when determining the steepness.
- So here it would be:
- Now, arrange them from least to greatest:
As you can see, 
is the smallest number/slope.
Hope this helps!
![\bf 2cos^2(x)+3cos(x)-2=0\impliedby \textit{so, notice is just a quadratic} \\\\\\\ [2cos(x)~~-~~1][cos(x)~~+~~2]=0\\\\ -------------------------------\\\\ 2cos(x)-1=0\implies 2cos(x)=1\implies cos(x)=\cfrac{1}{2} \\\\\\ \measuredangle x=cos^{-1}\left( \frac{1}{2} \right)\implies \measuredangle x= \begin{cases} \frac{\pi }{3}\\\\ \frac{5\pi }{3} \end{cases}\\\\ -------------------------------\\\\ cos(x)+2=0\implies cos(x)=-2](https://tex.z-dn.net/?f=%5Cbf%202cos%5E2%28x%29%2B3cos%28x%29-2%3D0%5Cimpliedby%20%5Ctextit%7Bso%2C%20notice%20is%20just%20a%20quadratic%7D%0A%5C%5C%5C%5C%5C%5C%5C%0A%5B2cos%28x%29~~-~~1%5D%5Bcos%28x%29~~%2B~~2%5D%3D0%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A2cos%28x%29-1%3D0%5Cimplies%202cos%28x%29%3D1%5Cimplies%20cos%28x%29%3D%5Ccfrac%7B1%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cmeasuredangle%20x%3Dcos%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5Cimplies%20%5Cmeasuredangle%20x%3D%0A%5Cbegin%7Bcases%7D%0A%5Cfrac%7B%5Cpi%20%7D%7B3%7D%5C%5C%5C%5C%0A%5Cfrac%7B5%5Cpi%20%7D%7B3%7D%0A%5Cend%7Bcases%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0Acos%28x%29%2B2%3D0%5Cimplies%20cos%28x%29%3D-2)
now, for the second case, recall that the cosine is always a value between -1 and 1, so a -2 is just a way to say, such angle doesn't exist.
Answer:
23
Step-by-step explanation:
100 is the exterior angle.
( 2x + 3 ) and 51 are interior angles.
Formula : -
Exterior angles = Sum of two interior angles.
100 = 2x + 3 + 51
100 = 2x + 54
2x = 100 - 54
2x = 46
x = 46 / 2
x = 23
Any function that has a -b value divided by 2a that equals -2
use ax²+bx+c to figure it out
the axis of symmetry formula is -b/2a=x
Answer: Quadrant III
Step-by-step explanation:
The slope is negative and the y-intercept is positive.
This means that it is impossible for both x and y to be negative, and thus it does not pass through <u>Quadrant III</u>
