Split up the interval [0, 2] into 4 subintervals, so that
![[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]](https://tex.z-dn.net/?f=%5B0%2C2%5D%3D%5Cleft%5B0%2C%5Cdfrac12%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac12%2C1%5Cright%5D%5Ccup%5Cleft%5B1%2C%5Cdfrac32%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac32%2C2%5Cright%5D)
Each subinterval has width
. The area of the trapezoid constructed on each subinterval is
, i.e. the average of the values of
at both endpoints of the subinterval times 1/2 over each subinterval
.
So,


Use the simple perimeter formula.
P = 2L + 2W
P = 2(9) + 2(5)
P = 19 + 10
P = 29ft
Therefore 29ft of fencing will be needed.
Answer:
19
Step-by-step explanation:
2d + 3
d = 8
2(8) + 3
multiply 2 and 8
16 + 3
add 16 and 3
= 19
Answer:
Step-by-step explanation: