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3 years ago

Population data from three towns is displayed in the tables below. Which town has growth that follows an exponential model?

Mathematics

1 answer:

Usimov [2.4K]3 years ago

7 0

Answer:

It would have to be D.

Step-by-step explanation:

None of the tables display an exponential growth of population.

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AysviL [449]

Answer:

Step-by-step explanation:

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2 years ago

HURRY PLEASEEEEEEEEEEE. A coordinate plane. The point (5, 5) is in Quadrant . The point (3, –2) is in Quadrant . The point (–4,

iVinArrow [24]

Answer:

point (5, 5) is in Quadrant: I (1)

point (3, –2) is in Quadrant: IV (4)

The point (–4, –4) is in Quadrant: III (3)

Step-by-step explanation:

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3 years ago

Read 2 more answers

HELP ME ASAP PLEASE!!

Daniel [21]

Answer:

set both of them equal to each other:

8x - 8° = 5x + 25°

subtract 5x by both sides of the equations and it becomes:

3x-8° = 25°

now add 8° both sides:

3x = 33°

divide three by both sides:

x = 11°

now thats done to find B:

plug your x value in the B equation:

5x + 25°

5(11) +25°

55 +25°

not sure if you can add here sorry :(. I hope this helped so far :)

5 0

3 years ago

Pam draws three scalene triangles. In each figure, she measures each angle, as shown.

Ganezh [65]

Answer:

the answer is c.

Step-by-step explanation:

there's no explanation

7 0

3 years ago

In the graph below, Point A represents Owen's house, Point B represents David's house and Point C represents the school. Who liv

ycow [4]

Answer:

• David

• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

• David's House, B(15,13)

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Owen's distance from school (AC)

$\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}$

David's distance from school (BC)

$\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}$

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding:

5 0

1 year ago