Ask question

Ask question

All categories

Mekhanik [1.2K]

2 years ago

11

An inscribed angle in a circle intercepts an arc whose measure is greater than 180

1 answer:

never [62]2 years ago

4 0

Answer:

The correct option is;

Never acute

Step-by-step explanation:

When an angle intercepts an ark, we have;

The legs of the angle meets with the endpoints of the arc

Therefore, given that the arc is greater than 180°, and that the angle of the arc is the angle defined at the center of the circle, while the angle defined by the inscribed angle is defined at the circumference of the circle

By circle theorem, the angle at the center is twice that at the circumference, whereby the angle of the arc > 180°, the angle at the subtended by the inscribed angle will > 180°/2, which is > 90° or an obtuse angle

You might be interested in

What is the different in the measures of angle WVX and angle WXV?

Yuri [45]

Answer:

wvx=57

wxv=180-149

=31

57-31

26

8 0

2 years ago

Let X be the number of Heads in 10 fair coin tosses. (a) Find the conditional PMF of X, given that the first two tosses both lan

inn [45]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

$P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}$

$= \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \ \ \\\\$

$k= 2,3..........10$ For option B:

$P(X=k | X \geq 2 ) = \sum^{10}_{i=2} \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}$

$k= 2,3, 4.........10$

8 0

3 years ago

PLS HELP ME W THIS QUESTION

QveST [7]

Answer:

<h2>A. 60 in³</h2>

Step-by-step explanation:

The formula of a volume of a cone:

$V=\dfrac{1}{3}\pi r^2H$

r - radius

H - height

We have r = 1.9 in and H = 15 in. Substitute:

$V=\dfrac{1}{3}\pi(1.9)^2(15)=\pi(3.61)(5)=18.05\pi\ in^3$

$\pi\approx3\to V\approx18.05\cdot3=54.15\ in^3$

7 0

2 years ago

Find the greatest common factor: 9a3bc2 + 12ac4 + 15a2b3c 3abc 15a3b3c4 3ac 9a2b2c2

VARVARA [1.3K]

The greatest common factor is 3abc

8 0

2 years ago

A basketball court is in the shape of a rectangle. It has a length of (x - 7) meters and a width of (x + 3) meters:

Molodets [167]

Answer:

x2 - 4x - 21

Step-by-step explanation:

Area = (x -7 )(x +3)

= x*x - 7*x + x*3 - 7*3

=x2 - 4x - 21

5 0

2 years ago