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2 years ago

11

Please i need help if you know it please let me know how you got it if u want if u dont its finee

2 answers:

inysia [295]2 years ago

5 0

To solve this we are using the Pythagorean Theorem which is c^2=a^2+b^2.

In this case the c (hypotenuse) is x. Our equation will look like this:

x^2=15^2+8^2
x^2=225+64
x^2=289
We do the square root to undo ^2
x = 17

Lilit [14]2 years ago

4 0

X=17 - hope this helps!

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A number cube labeled 1 to 6 is rolled 450 times. Which is the best prediction for the number of times that the number cube will

Vedmedyk [2.9K]

Haha, I don't think those answers belong to the question asked :P

The probability of rolling less than 3 is 2/6=1/3

So if you rolled 450 times you should expect to roll less than 3:

450(1/3)=150 times.

3 0

2 years ago

A bottom of a 6 foot deep circular pool has an area of 452.4 ft. If the pool is only

inna [77]

Answer:

450.4

Step-by-step explanation:

6 0

2 years ago

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Debora [2.8K]

Yo sup??

you can solve this quesion by having the knowledge of trigonometric ratios

let angle B be x, then

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x=66.8

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4 0

3 years ago

After 3.5 hours ,pasha had traveled 217 miles if she travels at the constant speed how far will she have travelled after 4 hours

vesna_86 [32]

Answer:

248 miles

Step-by-step explanation:

we know that

After 3.5 hours ,Pasha had traveled 217 miles

so

using proportion

Find out how many miles she will have traveled after 4 hours

$\frac{3.5}{217}\ \frac{hours}{miles}=\frac{4}{x}\ \frac{hours}{miles}\\\\x=217(4)/3.5\\\\x=248\ miles$

4 0

3 years ago

What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFrac

anastassius [24]

Answer:

$x =-24$

Step-by-step explanation:

Given

$(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3$

Required

Solve for x

$(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3$

Open all brackets

$\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x + \frac{1}{2}*14 - 3$

$\frac{2 * 1}{3 *2}x + \frac{2 * 12}{3}= \frac{1 * 1}{2 * 3}x + \frac{1 * 14}{2} - 3$

$\frac{1}{3}x + \frac{24}{3}= \frac{1}{6}x + \frac{14}{2} - 3$

$\frac{1}{3}x +8= \frac{1}{6}x + 7 - 3$

Collect like terms

$\frac{1}{3}x - \frac{1}{6}x =7 - 3 -8$

$\frac{1}{3}x - \frac{1}{6}x =-4$

Solve fraction

$\frac{2-1}{6}x =-4$

$\frac{1}{6}x =-4$

Multiply both sides by 6

$6 * \frac{1}{6}x =-4 * 6$

$x =-4 * 6$

$x =-24$

8 0

2 years ago