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skelet666 [1.2K]
3 years ago
12

Solve 9 - c = 17d for c

Mathematics
2 answers:
k0ka [10]3 years ago
5 0

Answer:

c = 9 - 17d

Step-by-step explanation:

9-c = 17d

9-c+c= 17d + c (add c to both sides)

9 = 17d + c (Simplify)

9 - 17d = 17d - 17d + c (subtract 17d from both sides)

9 - 17d = c (Simplify)

Nikitich [7]3 years ago
5 0

Answer:

c = - 17 d + 9 is what i got

Step-by-step explanation:

You might be interested in
Question 4) -6x + 9 + 6x -13<br> Your answer<br> Question 5) 8x - 9 -11 -14x<br> Your answer
Digiron [165]

Answer:

4) -4

5) -6x-20

Step-by-step explanation:

Add x with x's and numbers with numbers

4) -6x + 9 + 6x -13

-6x+6x+9-13

x's cancel

9-13 = -4

5) 8x - 9 -11 -14x

8x-14x-9-11

-6x-20

hope this helps

3 0
3 years ago
you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48
lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

\bar{x}=\frac{\sum X_i}{N}

The individual periods are Xi.

The sample size is N.

\sum X i = 1.06 + 1.31 + 1.28 + 0.99,+  1.48 + 1.37+  0.98 + 1.31 + 1.59 + 1.55

\sum X i = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}

\sum(x-\bar{x})^2 = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

\sum(x-\bar{x})^2 = 0.43996

Putting into the formula we get:

\sigma=\sqrt{\frac{0.43996}{10}}

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

#SPJ4

I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

7 0
2 years ago
I really need help with this question! And I need to show work
krek1111 [17]

Answer:

x=0.25 or -1/4

Step-by-step explanation:

120x + 21 = -9

120x = -30 (-21 from both sides of equation)

x = -0.25 or -1/4 (divide 120 from both sides of equation)

3 0
3 years ago
Read 2 more answers
Solve formula as indicated - d = 1/2 at^2 for a
11Alexandr11 [23.1K]
Hope this might help u

7 0
3 years ago
The diameter of a circle is 26 millimeters. What is the circle's circumference?
Shkiper50 [21]

Step-by-step explanation: the answer for this question should be 81.64 because to find the circumference you need to know the circumference formulas which is  C=TT times d or          C= 2 times TT times r.

C= 3.14 times 26          C= 2 times 3.14 times 13

                                       C= 81.64

C= 81.64

so the answer is 81.64 for the circle's circumference so hopefully that is the correct answer and have a great day

                       

7 0
2 years ago
Read 2 more answers
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