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2 years ago

So im new how exactly does this point system work???

Computers and Technology

1 answer:

lapo4ka [179]2 years ago

5 0

Answer:

Ok so basicly every time you see a question and you can answer it you press on the answer bar you type in your answers then you will automaticly get points depending on the question you answer, you need to get more than 5+ to ask a question of your own

Explanation:

You might be interested in

Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria

butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

if side1 == side2 == side3:

print("Equilateral Triangle")

elif side1 == side2 or side1 == side3 or side2 == side3:

print("Isosceles Triangle")

else:

print("Scalene Triangle")

else:

print("Invalid Triangle")

else:

print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

if side1 == side2 == side3:

print("Equilateral Triangle")

Check if the triangle is isosceles

elif side1 == side2 or side1 == side3 or side2 == side3:

print("Isosceles Triangle")

Otherwise, it is scalene

else:

print("Scalene Triangle")

Print invalid, if the sides do not make a valid triangle

else:

print("Invalid Triangle")

Print invalid, if the any of the sides are negative

else:

print("Invalid Triangle")

4 0

3 years ago

A combination lock has the following basic properties:

fomenos

Answer:

public class CombinationLock {

private int combinationNumber1 = 0;

private int combinationNumber2 = 0;

private int combinationNumber3 = 0;

CombinationLock(int combinationNumber1, int combinationNumber2, int combinationNumber3){

this.combinationNumber1 = combinationNumber1;

this.combinationNumber2 = combinationNumber2;

this.combinationNumber3 = combinationNumber3;

}

public boolean open(int number1, int number2, int number3){

if(number1 == combinationNumber1 && number2 == combinationNumber2 && number3 == combinationNumber3)

return true;

else

return false;

}

public boolean changeCombo(int number1, int number2, int number3, int newNumber1, int newNumber2, int newNumber3){

if (open(number1, number2, number3)){

combinationNumber1 = newNumber1;

combinationNumber2 = newNumber2;

combinationNumber3 = newNumber3;

return true;

}else

return false;

}

Explanation:

- Three variables are created to hold the combination.

- A constructor is created to set the combination.

- A boolean method called open is created to check if the given numbers are correct, and returns true (otherwise returns false).

- A boolean method method called changeCombo is created to check if given numbers are correct. If they are correct, it assigns new values for the combination and returns true (otherwise returns false).

5 0

2 years ago

What is a data source in OLE?

babunello [35]

Answer:

OLE DB Driver for SQL Server uses the term data source for the set of OLE DB interfaces used to establish a link to a data store, such as SQL Server. Creating an instance of the data source object of the provider is the first task of an OLE DB Driver for SQL Server consumer.

Explanation:

hope it helps you and give me a brainliest

6 0

1 year ago

Which tab in Microsoft Word provides access to the backstage view?

ivann1987 [24]

The answer is control windows

6 0

3 years ago

Read 2 more answers

A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co

tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k ...(1)

probability of 2 hops = k(1-k) ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

= (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

= k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

∞ n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

n-1

= 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet = k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet = $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

6 0

3 years ago

So im new how exactly does this point system work???​

So im new how exactly does this point system work???