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puteri [66]
3 years ago
10

In the welding operations of a bicycle manufacturer, a bike frame has a long flow time. The set up for the bike frame is a 7 hou

r long operation. After the setup, the processing takes 6 hour(s). Finally, the bike frame waits in a storage space for 7 hours before sold. Determine the value-added percentage of the flow time for this bike frame. Round your answer to the nearest whole number for percentage and do NOT include the "%" sign in the answer. For example, if your answer is 17.7%, please answer 18. If your answer is 17.4%, please answer 17. No "%" sign. No letter. No symbols. No explanation. Just an integer number.
Computers and Technology
1 answer:
mestny [16]3 years ago
8 0

Answer:

Bike Frame Flow Time

The value-added percentage of the flow time for this bike frame is:

= 46.

Explanation:

a) Data and Calculations:

Bike Frame Flow Time:

Setup time = 7 hours

Processing time = 6 hours

Storage time = 7 hours

Flow time of the bike frame = 13 hours (7 + 6)

Value-added percentage of the flow time for this bike frame = 6/13 * 100

= 46%

b) Flow time represents the amount of time a bicycle frame spends in the manufacturing process from setup to end.  It is called the total processing time. Unless there is one path through the process, the flow time equals the length of the longest process path.  The storage time is not included in the flow time since it is not a manufacturing process.

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The algorithm is as follows:

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Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
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3 years ago
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