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3 years ago

Find the value of c ÷ 6 when c = 42.

Mathematics

2 answers:

Lerok [7]3 years ago

8 0

Answer:

Step-by-step explanation:

42/6=7

Sergio [31]3 years ago

7 0

Answer:

Step-by-step explanation:

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2(4x - 12) + 3x = 6x + 1<br><br> help!! ahh

Anuta_ua [19.1K]

<span>2(4x - 12) + 3x = 6x + 1

Distribute.

8x - 24 + 3x = 6x + 1

Combine like terms.

11x - 24 = 6x + 1

5x = 25

x = 5

</span>

8 0

3 years ago

Read 2 more answers

Solve for x and y in the parallelogram

Lubov Fominskaja [6]

Answer:

x=3

y=6

Step-by-step explanation:

Hope this helps! :)

4 0

3 years ago

What is the solution to -x2 + 5x - 3

CaHeK987 [17]

The solution to the equation is $x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

Explanation:

Given that the equation is $-x^2+5x-3=0$

We need to determine the solution of the equation.

The solution of the equation can be determined using the quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Hence, from the equation, we have,

$a=-1,\:b=5,\:c=-3$

Substituting these values in the quadratic formula, we get,

$x=\frac{-5\pm \sqrt{5^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)}$

Simplifying, we get,

$x=\frac{-5\pm \sqrt{25-12}}{-2}$

Simplifying the terms within the root, we get,

$x=\frac{-5\pm \sqrt{13}}{-2}$

Thus, the roots of the equation are $x=\frac{-5+ \sqrt{13}}{-2}$ and $x=\frac{-5- \sqrt{13}}{-2}$

Taking out the negative sign, we get,

$x=\frac{-(5- \sqrt{13})}{-2}$ and $x=\frac{-(5+ \sqrt{13})}{-2}$

Cancelling the negative sign, we get,

$x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

Thus, the solutions of the equation are $x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

7 0

3 years ago

4x^4+1+3x^3+2x by x^2+x+2

Norma-Jean [14]

8 + -3x-15/2x^2+×+2 should be the correct answer.

7 0

3 years ago

How do you solve X/2-5=10

Afina-wow [57]

Answer: x2-5=10

Two solutions were found :

x = ± √15 = ± 3.8730

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x^2-5-(10)=0

Step by step solution :

Step 1 :

Trying to factor as a Difference of Squares :

1.1 Factoring: x2-15

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 15 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step 1 :

x2 - 15 = 0

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : x2-15 = 0

Add 15 to both sides of the equation :

x2 = 15

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

x = ± √ 15

The equation has two real solutions

These solutions are x = ± √15 = ± 3.8730

Two solutions were found :

x = ± √15 = ± 3.8730

Step-by-step explanation:

5 0

3 years ago