A = 1/2 (base * height)
A = 1/2 [(x^2 + 2x + 4)*(<span>2x^2 + 2x + 6)]</span>
A = 1/2 [(x^2 + 2x + 4)*(<span>2x^2 + 2x + 6)]</span>
a 4 +4a 2 b 2 −2b 4 a, start superscript, 4, end superscript, plus, 4, a, squared, b, squared, minus, 2, b, start superscript, 4
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Answer:
Step-by-step explanation:
Recall that
We know that
Note that according to the definition of it is true that both sine and cosine are negative, once
. Because
, this conclusion is true. We basically have
Sure it is true but perhaps this way is better to understand.
In order to find sine, we can use the definition and manipulate the rational expression.
Therefore,
Here I just divided numerator and denominator by .
Now, to find cosine we can use the identity
Thus,
Once we have , we just consider
FInally, for tangent, just consider
thus,