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Shkiper50 [21]
3 years ago
6

Function A and Function B are linear functions. Compare the two functions and choose all that are correct. Can someone help?

Mathematics
1 answer:
iris [78.8K]3 years ago
6 0

Answer:

(b) and (c) are true

Step-by-step explanation:

Given

Function A and B

First, calculate the slope of A

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{24 - -21}{8- -7}

m = \frac{45}{15}

m  =3

The equation of function A is:

y = m(x - x_1) + y_1

y = 3(x - 8) + 24

y = 3x - 24 + 24

y = 3x

The general form of a function is:

y = mx + b

Where m = slope and b = y\ intercept.

This implies that:

Slope = 3

Y\ intercept = 0

For function B:

y = 4x - 3

Slope = 4

Y\ intercept = -3

By comparison:

(b) and (c) are true

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4 0
3 years ago
Read 2 more answers
abcd is an isosceles trapezoid with legs ab and cd and base bc if the length of ab =-3y+54 the leingth of bc =5y+2 and the leing
Vilka [71]

ANSWER

y = 5

EXPLANATION

The given isosceles tra-pezoid has legs

ab =  - 3y + 54

and

cd = 6y + 9

The base is bc=5y+2.

The length of the legs of the isosceles tra-pezoid are equal.

This implies that,

ab = cd

Thus,

- 3y + 54 = 6y + 9

Group similar terms,

54 - 9 = 6y + 3y

45 = 9y

Divide both sides by 9.

y =  \frac{45}{9}

y = 5

8 0
3 years ago
Help me with these math questions....
Nady [450]

Answer: cotθ

<u>Step-by-step explanation:</u>

 tanθ * cos²θ * csc²θ

=  \dfrac{sin\theta}{cos\theta} * \dfrac{cos\theta*cos\theta}{} *\dfrac{1}{sin\theta*sin\theta}

= \dfrac{cos\theta}{sin\theta}

= cotθ

Answer: B

<u>Step-by-step explanation:</u>

The parent graph is y = x²

The new graph y = -x² + 3 should have the following:

  • reflection over the x-axis
  • vertical shift up 3 units

Answers:

  • a. Quadrant II
  • b. negative
  • c. \dfrac{\pi}{6}
  • d. C
  • e.-\dfrac{\sqrt{3}}{3}

<u>Explanation:</u>

\dfrac{17\pi}{6} - \dfrac{12\pi}{6} = \dfrac{5\pi}{6}

a) Quadrant 2 is: \dfrac{\pi}{2} < \theta < \pi

b) In Quadrant 2, cos is negative and sin is positive, so tan is negative

c) \pi-\dfrac{5\pi}{6} = \dfrac{\pi}{6}

d) the reference line is above the x-axis so it is negative -->  -tan\dfrac{\pi}{6}

e) tan(\dfrac{5\pi}{6})=\dfrac{1}{-\sqrt{3}}=-\dfrac{\sqrt{3}}{3}


4 0
3 years ago
What is the absolute value of 2 1/2<br><br> Write your answer as a mixed number.
Greeley [361]

Answer:

it is 2 1/2

Step-by-step explanation:

I hope this helps

6 0
3 years ago
SOMOEN DELETED ALL MY ASNWERS NOW I ONLY HAVE 13 POINTS WHY WHY WHYYYYYYYYY
Vedmedyk [2.9K]

Answer:

Maybe its because you give useless answers to get points.

Idiot.

7 0
2 years ago
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