What are the necessary criteria for a line to be perpendicular to the given line and have the same y-intercept?
2 answers:
Answer:
The slope is -3/2 and contains the point (0, −2). Which is b.
Step-by-step explanation:
(-3,-4) (3, 0)
slope = (0 +4) / (3 + 3) = 4/6 = 2/3
perpendicular so slope = -3/2
line on graph
y = mx + b
0 = 2/3 (3) + b
0 = 2+ b
b = -2
y intercept (0,-2)
Y=-(3/5)x-7is the anwser because this is the form y=mx+b where m=5/3 any line perpendicular to this given line will have the slope of -1/m so, in this case slope of perpendicular is: -1/(5/3) = -3/5 we know the y-intercept is -7, point (0, -7) so wave: <span>y = -(3/5)x - 7</span>
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X = y - 8
Step-by-step explanation:
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= 160 cm^3
density = mass/vol of displaced water
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= 19.3 g/cm^3
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Answer:
Answer: correct answer is B.(2x+3y)(4x^2-6xy+9y^2)
8x^3 + 27y^3
(2x)^3+(3y)^3
(2x+3y)(4x^2-6xy+9y^2) <----answer
