You have 0.2 liter of an acid solution whose acid concentration is 16 moles per liter. You want to dilute the solution with wate
r so that its acid concentration is only 12 moles per liter. Use the given model todetermine howmany liters of water you should add to the solution.
2 answers:
Answer: normally 0. 067 but if you are using big ideas you'd round it so it would become
0. 07
Step-by-step explanation:
12 = 16 (0.2) / (0.2 + w)
(0.2 + w) * 12 = 3.2
0.2 + w = 3.2 / 12
w = (3.2 / 12) - 0.2
Answer: 0.067 litres of water
Step-by-step explanation:
The mode is:
Concentration of new solution = Moles of acid in original solution / (Volume of original solution + Volume of water added)
Assume volume of water added is w.
12 = 16 (0.2) / (0.2 + w)
(0.2 + w) * 12 = 3.2
0.2 + w = 3.2 / 12
w = (3.2 / 12) - 0.2
w = 0.067 litres of water
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