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Andru [333]
2 years ago
15

A lake in East Texas was stocked with 3,000 trout in the year 2000. The number of fish in the lake is modeled by f(x) = 3000 + 1

00x, where x represents the number of years after 2000. Which of the following is the most reasonable domain and range for the function?
Mathematics
1 answer:
Maru [420]2 years ago
5 0

Answer: x ≥0,y ≥3000

Step-by-step explanation:

that’s what i put and got it right so ‍♀️

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Will the two gardens be the same size? Explain why or why not.
Irina-Kira [14]
No the gardens are not going to be the same because Jamal' s garden is bigger than marks garden
5 0
3 years ago
Which value of k makes the inequality 11+2k>19 true?
Vadim26 [7]

Answer:

6.

Step-by-step explanation:

11 + 2k > 19

2k > 19 - 11

2k > 8

k > 8/2

k > 4.

4 0
3 years ago
Babies born after 40 weeks gestation have a mean length of 52.2 centimeters (about 20.6 inches). Babies born one month early hav
Sveta_85 [38]

Answer:

a) Z = -2.88

b) Z = -0.96

c) 40 weeks gestation babies

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. Find the standardized score (z-score), relative to all U.S. births, for a baby with a birth length of 45 cm.

Here, we use \mu = 52.2, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 52.2}{2.5}

Z = -2.88

b. Find the standardized score of a birth length of 45 cm. for babies born one month early, using 47.4 as the mean.

Here, we use \mu = 47.4, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 47.4}{2.5}

Z = -0.96

c. For which group is a birth length of 45 cm more common?

For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

3 0
3 years ago
Can someone help me with my work
juin [17]
F(x) = x
stretch by 3:
f(x) = 3x

flip over x-axis
g(x) = -3x

answer is C. g(x) = -3x


5 0
3 years ago
If 13 - 3z= 15z +4, z = ?
jasenka [17]

Answer:

z = 1/2 or 0.5

Step-by-step explanation:

13 - 3z = 15z + 4

   +3z    +3z

  13 = 18z + 4

  -4            -4  

      9 = 18z

      z = 9/18

      z = 1/2 or 0.5

3 0
3 years ago
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