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2 years ago

Can someone please help me answer this question

Mathematics

2 answers:

Allushta [10]2 years ago

7 0

Answer:

720

Step-by-step explanation:

60 minutes in a hour. So add 30 for each 20 minutes so it would be 90 an hour so multiply 90 by 8

igomit [66]2 years ago

7 0

Answer:

720 widgets

Step-by-step explanation:

there are 60 minutes in hour

multiply that by 8 hours

you get 480

divide that by 20

multiply that by 30

the answer is 720 widgets

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TEA [102]

Answer:

9. 40°

10. 50°

11. 270°

12. 310°

Step-by-step explanation:

m∠BPC = 40° because it is complementary to ∠APB, which is 50°.

Arc AB is 50° because it will be equal to the central angle, which is 50°.

Arc ADC is 270° because it will be equal to the central angle, which is 270°.

Arc ADB is 310° because it will be equal to the central angle, also 310°.

6 0

3 years ago

Which is faster 15 feet per second or 12 miles per hour

Ierofanga [76]

12 miles per hour, it’ll be 17.6 feet per second.

6 0

3 years ago

Read 2 more answers

1 point Write the equation of the line that is parallel to the line given and through the given point. Do not use spaces in your

Otrada [13]

Answer:

y=3x+9......(i)

y=-4x-12...(ii)

these are the equation

5 0

3 years ago

5 —— —— i need help!! ————- math geniuses pls help me!

34kurt

Answer:

Step-by-step explanation:

x = 7 cos (2pi/3) y = 7 sin (2pi/3)

x = -7/2 y = 7 sqrt(3) /2

5 0

1 year ago

Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

liq [111]

For the given equation;

$(3x-5)^2=-125$

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

$\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}$

Now that we have expanded the left side of the equation, we would have;

$\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}$

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}$

ANSWER:

$x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}$

3 0

11 months ago