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3 years ago

Can someone help me with 1 and 2? First to answer will receive brainliest!

Mathematics

1 answer:

Anon25 [30]3 years ago

5 0

Answer:

<h2><u>Required Answer</u><u>:</u><u>-</u></h2>

A (-1,3) and B(0,7)

${:}\longmapsto$ $\sf AB=\sqrt {(x_2-x_1)^2+(y_2-y _1)^2}$

${:}\longmapsto$ $\sf AB=\sqrt {(0+1)^2+(7-3)^2}$

${:}\longmapsto$ $\sf \sqrt{1^2+4^2}$

${:}\longmapsto$ $\sf \sqrt {1+16}$

${:}\longmapsto$ $\sf AB=\sqrt{17}$

Hence option C is correct

__________________________

2-A (-3,4)

If it rotates 180° Then The sign changes

${:}\longmapsto$ $\sf (3,-4)$

Hence option D is correct

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Anarel [89]

Answer:

101

Step-by-step explanation:

If you add up all of the answers, it equals 101 due to the fact of just adding all of the x's together in a row.

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Find two positive numbers so that twice their sum equals their product and one number is 3 times the other number. Enter the sma

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X and y

2(x+y)=xy
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x=3y

easy, sub 3y for x

2(3y+y)=(3y)y
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4 years ago

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1. A tree 5 ft tall grows an average of 8 in. each year. Which equation models the trees height h after x years?

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Well we know that it grows 8 in a year. so after 1 year has grown 1 * 8 and after 2 years 2 * 8 and after 3 years 3 * 8 and so on. since x is the year we can say 8x. but it starts with 5 ft so we add in the 5 to get h.
h = 8x + 5

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4 years ago

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4 years ago

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What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)squared + 4?

Artyom0805 [142]

Answer:

x = 3/2

Step-by-step explanation:

That is quite long and drawn out, so we have to get it down to a single quadratic equation, set equal to 0.

Begin by expanding the right side to get

$y+3x-6=-3(x^2-4x+4)+4$

then multiplying in the -3 to get

$y+3x-6=-3x^2+12x-12+4$

Now we will combine all the like terms and get everything on one side of the equals sign, and set it equal to 0:

$-3x^2+9x-2=0$

In order to find the equation of the axis of symmetry we have to put it into vertex form, which is accomplished by completing the square on this quadratic.

In order to complete the square, the leading coefficient has to be a +1. Ours is a -3, so we will factor that out. First, though, now that it is set to equal 0, we will move the constant, -2, over to the other side, isolating the x terms.

$-3x^2+9x=2$

Now we can factor out the -3:

$-3(x^2-3x)=2$

The rules for completing the square are as follows:

Take half the linear term, square it, and add it to both sides. Our linear term is 3. Half of 3 is 3/2, and squaring that gives you 9/4. We add into the parenthesis on the left a 9/4, but don't forget about that -3 hanging around out front that refuses to be ignored. We didn't add in just a 9/4, we added in (-3)(9/4) = -27/4:

$-3(x^2-3x+\frac{9}{4})=2-\frac{27}{4}$

In the process of completing the square we created a perfect square binomial on the left. Stating that binomial and simplifying the addition on the right gives us:

$-3(x-\frac{3}{2})^2=-\frac{19}{4}$

We can determine the axis of symmetry at this point. Because this is a positive x-squared polynomial, the axis of symmetry is in the form of (x = ) and what it equals is the h coordinate of the vertex. Our h coordinate is 3/2; therefore, the axis of symmetry has the equation x = 3/2

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