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Svetlanka [38]
3 years ago
13

3 4 ÷ 5 12 = 3 answer quick for brainly 4 ×

Mathematics
1 answer:
tresset_1 [31]3 years ago
3 0

Answer:

12

Step-by-step explanation:

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If there is a graph or something that you can show me, I'd be more than happy to help you.
4 0
3 years ago
What's the answer to this
timofeeve [1]

Answer:

AC ≈ 17.3 , BC ≈ 5.3

Step-by-step explanation:

using the tangent ratio in right triangle ACD

tan51° = \frac{opposite}{adjacent} = \frac{AC}{AD} = \frac{AC}{14} ( multiply both sides by 14 )

14 × tan51° = AC , then

AC ≈ 17.3 ( to the nearest tenth )

using the cosine ratio in right triangle ABC

cos72° = \frac{adjacent}{hypotenuse} = \frac{BC}{AC} = \frac{BC}{17.3} ( multiply both sides by 17.3 )

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5 0
2 years ago
A team of 9 tennis players can order bags with their uniforms
jeka94

Answer:

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Step-by-step explanation:

5 0
3 years ago
IF YOU ANSWER THIS I WILL GIVE YOU BRAINLIEST!! 21PTS
vovangra [49]
<span>200 < 225 + 80x < 550

The 200 is the amount the Jenna currently have. 
225 + 80x is the amount that Jenna has to pay given x number of hours.
550 is the sum of Jenna's 200 and additional 350 she can get by selling pre-ordered Cds. This is the maximum amount she can pay for the studio rental and sound technicians.

225 + 80x < 550
80x < 550 -225
80x < 325
80x / 80 < 325/80
x < 4.06 or 4 hours

225 + 80x </span>→ 225 + 80(4) = 225 + 320 = 545
<span>
The number of hours for the sound technician will range from 1 hour to 4 hours. 

Assuming they will use 6 hours.

225 + 80(6) = 225 + 480 = 705
705 - 550 = 155

Jenna has to raise an additional $155 to pay off the studio rent and 6 hours of sound technicians. 


</span>
4 0
3 years ago
Show solutions please
slega [8]

Answer:

1. Their ages are:

Steve's age = 18

Anne's age = 8

2. Their ages are:

Max's age = 17

Bert's age = 11

3. Their ages are:

Sury's age = 19

Billy's age = 9

4. Their ages are:

The man's age = 30

His son's age = 10

Step-by-step explanation:

1. We make the assumption that:

S = Steve's age

A = Anne's age

In four years, we are going to have:

S + 4 = (A + 4)2 - 2 = 2A + 8 - 2

S + 4 = 2A + 6 .................. (1)

Three years ago, we had:

S - 3 = (A - 3)3

S - 3 = 3A - 9

S = 3A - 9 + 3

S = 3A – 6 …………. (2)

Substitute S from (2) into (1) and solve for A, we have:

3A – 6 + 4 = 2A + 6

3A – 2A = 6 + 6 – 4

A = 8

Substitute A = 8 into (3), we have:

S = (3 * 8) – 6 = 24 – 6

S = 18

Therefore, we have:

Steve's age = 18

Anne's age = 8.

2. We make the assumption that:

M = Max's age

B = Bert's age

Five years ago, we had:

M - 5 = (B - 5)2

M - 5 = 2B - 10 .......................... (3)

A year from now, it will be:

(M + 1) + (B + 1) = 30

M + 1 + B + 1 = 30

M + B + 2 = 30

M = 30 – 2 – B

M = 28 – B …………………… (4)

Substitute M from (4) into (3) and solve for B, we have:

28 – B – 5 = 2B – 10

28 – 5 + 10 = 2B + B

33 = 3B

B = 33 / 3

B = 11

If we substitute B = 11 into equation (4), we will have:

M = 28 – 11

M = 17

Therefore, their ages are:

Max's age = 17

Bert's age = 11.

3. We make the assumption that:

S = Sury's age

B = Billy's age

Now, we have:

S = B + 10 ................................ (5)

Next year, it will be:

S + 1 = (B + 1)2

S + 1 = 2B + 2 .......................... (6)

Substituting S from equation (5) into equation (6) and solve for B, we will have:

B + 10 + 1 = 2B + 2

10 + 1 – 2 = 2B – B

B = 9

Substituting B = 9 into equation (5), we have:

S = 9 + 10

S = 19

Therefore, their ages are:

Sury's age = 19

Billy's age = 9.

4. We make the assumption that:

M = The man's age

S = His son's age

Therefore, now, we have:

M = 3S ................................... (7)

Five years ago, we had:

M - 5 = (S - 5)5

M - 5 = 5S - 25 ................ (8)

Substituting M = 3S from (7) into (8) and solve for S, we have:

3S - 5 = 5S – 25

3S – 5S = - 25 + 5

-2S = - 20

S = -20 / -2

S = 10

Substituting S = 10 into equation (7), we have:

M = 3 * 10 = 30

Therefore, their ages are:

The man's age = 30

His son's age = 10

3 0
3 years ago
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