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2 years ago

IF YOU ANSWER THIS I WILL GIVE YOU BRAINLIEST!! 21PTS

1 answer:

4 0

200 < 225 + 80x < 550

The 200 is the amount the Jenna currently have.
225 + 80x is the amount that Jenna has to pay given x number of hours.
550 is the sum of Jenna's 200 and additional 350 she can get by selling pre-ordered Cds. This is the maximum amount she can pay for the studio rental and sound technicians.

225 + 80x < 550
80x < 550 -225
80x < 325
80x / 80 < 325/80
x < 4.06 or 4 hours

225 + 80x → 225 + 80(4) = 225 + 320 = 545

The number of hours for the sound technician will range from 1 hour to 4 hours.

Assuming they will use 6 hours.

225 + 80(6) = 225 + 480 = 705
705 - 550 = 155

Jenna has to raise an additional $155 to pay off the studio rent and 6 hours of sound technicians.

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Simplify the expression 2p + 3/4p + 6 - p - 3 1/2

lozanna [386]

Answer:

The simplified expression is "7p/4 + 2 1/2" or "1.75p + 2.5".

Step-by-step explanation:

2p + 3/4p + 6 - p - 3 1/2
=> (2p - p + 3/4p) + (6 - 3.5)
=> 1.75p + 2.5

Hence, the simplified expression is "7p/4 + 2 1/2" or "1.75p + 2.5". Any of these would work.

Hoped this helped.

$BrainiacUser1357$

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2 years ago

On a coordinate plane, a line connects (negative 4, negative 5) and (negative 2, negative 4), a curve connects (negative 2, nega

statuscvo [17]

Answer: f^-1(4)= 2 f^-1(-5)= -4 f^-1(0)= 0

Step-by-step explanation:

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2 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

Answers with step-by-step explanation:

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

2 years ago

Consider firing a pumpkin from a canon at a target that is 17 meters away. The pumpkin follows a quadratic path as displayed to

bixtya [17]

A.
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)

b.
well, the points don't look like they are on the line but they actually are (plot twist)

so
since (0,0) is on th egarph

0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx

find a and b
sub points

(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b

(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b

use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b

eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b

-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b

12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b

da equation is
$y= \frac{-5.68}{27.456} x^2+ \frac{12.4+\frac{130.8672}{27.456}}{4.8}x$

c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target

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3 years ago

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daser333 [38]

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2 years ago