Answer:
Yes, in a Cartesian Coordinate system each point is given by two numbers. If the question is "where" the function has a max or min value, that's "x", the first number in pair. If the question is "what" is that max or min function value, thats "y", the second number in the pair
Answer:
$52091.95
Step-by-step explanation:
From the given information:
The number of cities visited = 14
Cost of each cooking demonstration = $3450
The total cost of cooking demonstration = $3450 × 14
= $48300
Book signing material = $1475
∴
The total cost of cooking demonstration and book material is:
= $48300 + $1475 = $49775 ---- (i)
Total meter traveled in visiting 14 cities = 240 * 13 = 3120 miles
However; suppose the weekly rental fee fine = $x &
the change per mile = $y
Then
y*540 + x = 1188.15 --- (ii)
y*880 + x = 1310.55 --- (iii)
From equation (ii) and (iii)
y *340 = 122.4
y = 122.4/340
y = 0.36
From (ii)
y × 540 + x = 1188.15
(0.36)540 + x = 1188.15
x = 1188.15 - (0.36)540
x = 993.75
Hence, the total cost of travelling by RV camper = $1993.75 + 3120 × (0.36)
= $2116.95
Thus, the total amount the publisher should budget = $49975.0 + $2116.95
= $52091.95
Answer: w² equals to 28.2
To solve this problem, we need to get the variable x alone on one side of the equation. To begin, we are going to use the distributive property twice on the left side of the equation to expand the multiplication and get rid of the parentheses.
4(x-1) - 2(3x + 5) = -3x -1
4x - 4 -6x - 10 = -3x - 1
Next, we should combine like terms on the left side of the equation. This means we should add/subtract the variable terms and the constant terms in order to simplify this equation further.
-2x - 14 = -3x - 1
Then, we have to add 3x to both sides of the equation to get the variable terms all on the left side of the equation.
x - 14 = -1
After that, we should add 14 to both sides of the equation to get the variable x alone one the left side of the equation.
x = 13
Therefore, the answer is 13.
Hope this helps!
There is 16 ounces in a pound, and #1 is B I believe
