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liraira [26]
3 years ago
15

The graph below has the same shape. what is the equation of the graph?

Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0

C; A and B are incorrect because the shift is not vertical, it is horizontal. This is because 3 is in parenthesis or a 'grouping' (same thing if it is in an exponent) and is being modified. Since the graph is being translated down 3 units, D is incorrect since it is a translation up 3 units. The answer is C.

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Find the missing side length of the right triangle shown. Round to the nearest tenth, if
Delvig [45]

Answer:

? = 26 in

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

?² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )

? = \sqrt{676} = 26

4 0
3 years ago
Read 2 more answers
Please answer this! I'll classify you as brainliest, okay here it goes: what is x3+y3=z3. ( the3 is an exponent)
koban [17]

Answer:

30

Step-by-step explanation:

4 0
3 years ago
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
3 years ago
What type of triangle is this triangle?
olga2289 [7]
It’s isosceles because 2 acute angles and one 90 degree angle makes an isosceles triangle
8 0
2 years ago
Please help with these two questions...<br>I'll give you brainliest and I'll give you likes
bekas [8.4K]

Answer:

GH= 65.75

x=44.25

Step-by-step explanation:

I'm not so sure don't take my word for it I just wanted to try because I'm also new to geometry.

4 0
3 years ago
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