All categories

3 years ago

NEED HELP!! the graph shows the volume of oil in a tank at time t seconds

Mathematics

1 answer:

OlgaM077 [116]3 years ago

4 0

Answer:

Part a: 2.5

Part b: The rate the oil fills the tank

Part c: The amount of liquid in the tank to begin with.

Hope this helps. :)

You might be interested in

2² + {[1 x (5 - 2)] x 3

alexandr1967 [171]

Answer:

The answer is 13

Step-by-step explanation:

Hope this helps :)

5 0

3 years ago

A shape is shown on the graph: A coordinate plane is shown. Triangle ABC has vertices 3 comma 0, 3 comma negative 3, and 1 comma

soldi70 [24.7K]

What are the given answers?

6 0

3 years ago

Suppose that $a$ is a positive integer for which the least common multiple of $a+1$ and $a-5$ is $10508$. What is $a^2 - 4a + 1$

Nana76 [90]

Answer:

21022.

Step-by-step explanation:

Find the prime factors of 10508:

2 ) 10508

2 ) 5254

37 ) 2627

71.

50208 = 2*2*37*71.

Now there is no integer value for a that would fit (a+ 1)(a - 5) = 10508 .

But we could try multiplying the LCM by 2:-

= 21016 = 2*2*2*37*71.

= 2*2*37 multiplied by 2 * 71

= 148 * 142.

That looks promising!!

a - 5 = 142 and

a + 1 = 148

This gives 2a - 4 = 290

2a = 294

a = 147.

So substituting a = 147 into a^2 - 4a + 1 we get:

= 21022.

4 0

3 years ago

Please help I’d appreciate it I don’t understand thank you

Alexus [3.1K]

Your answer is the 3rd option.

$c = \pi \times d$
You must divide by π on both sides, therefore d=c/π

4 0

3 years ago

The area of a square in square feet is

Sedaia [141]

Answer:

Part 1) The expression for the perimeter is $P=4(25z-3)$ or $P=100z-12$

Part 2) The perimeter when z = 15 ft. is $P=1,488\ ft$

Step-by-step explanation:

Part 1)

we have

$625z^{2}-150z+9$

Find the roots of the quadratic equation

Equate the equation to zero

$625z^{2}-150z+9=0$

Complete the square

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$625z^{2}-150z=-9$

Factor the leading coefficient

$625(z^{2}-(150/625)z)=-9$

$625(z^{2}-(6/25)z)=-9$

Complete the square. Remember to balance the equation by adding the same constants to each side

$625(z^{2}-(6/25)z+(36/2,500))=-9+(36/4)$

$625(z^{2}-(6/25)z+(36/2,500))=0$

Rewrite as perfect squares

$625(z-6/50)^{2}=0$

$z=6/50=0.12$ -----> root with multiplicity 2

The area is equal to

$A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}$

The length side of the square is $b=(25z-3)$

therefore

The perimeter is equal to

$P=4b$

$P=4(25z-3)$

$P=100z-12$

Part 2) Find the perimeter when z = 15 ft.

we have

$P=100z-12$

substitute the value of z

$P=100(15)-12=1,488\ ft$

4 0

3 years ago