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3 years ago

PLEASE HELP ILL GIVE YOU MAX POINTS SAY THANKS AND GIVE BRAIN

Mathematics

2 answers:

kramer3 years ago

4 0

Answer:

The answer is C, use a calculator and you'll get the answer.

Angelina_Jolie [31]3 years ago

3 0

Answer:

Step-by-step explanation:

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If the product of the two slopes of two lines equals -1, then the lines are ?

VladimirAG [237]

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{a}{b}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{b}{a}}\qquad \stackrel{negative~reciprocal}{-\cfrac{b}{a}}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \left( \cfrac{a}{b} \right)\left( -\cfrac{b}{a} \right)=-1~\hfill$

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2 years ago

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qaws [65]

Answer:

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7 0

2 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

2 years ago

In a circle with an 8-inch radius, a central angle has a measure of 60°. How long is the segment joining the endpoints of the ar

g100num [7]

Given the radius, circumference can be solved by the equation, C = 2πr. The circumference of the circle above is C = 2π(8 in) = 16<span>π in. To solve for the length of the segment joining the arc is the circumference times the ratio of central angle and 360 degrees.

Length of the segment = (16</span>π in)(60/360) = 8/3 <span>π in

Thus, the length of the segment is approximately 8.36 in. </span>

3 0

3 years ago

Read 2 more answers

HELP FAST IT'S TIMED

anygoal [31]

Answer:

d = 1/2

Step-by-step explanation:

5/6 = 1/3 + d

~Find common denominators

5/6 = 2/6 + d

~Subtract 2/6 to both sides

3/6 = d

~Simplify

1/2 = d

Best of Luck!

4 0

2 years ago

Read 2 more answers