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MariettaO [177]
2 years ago
14

5. Find the scale factor, if an aardvark is 130cm long (without the tail), and it 1 point

Mathematics
1 answer:
-Dominant- [34]2 years ago
7 0
<h3>Answer:  16.67</h3>

Explanation:

Divide the two values to get the scale factor.

130/7.8 = 16.67

This means the aardvark in real life is roughly 16.67 times longer compared to its drawn version on paper.

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Solve for m and b <br><br>(5,14) and (3,10)​
Elis [28]
Y=mx+b

Y1-Y2/X1-X2

14-10/5-3 = 4/2 = 2


Plug in (3,10):
(10)=2(3)+b

Solve:
10=6+b

B=4
M=2
6 0
3 years ago
A trapezoid has base lengths of 12 centimeters and 13 centimeters. The other sides have lengths of 5 centimeters and 10 centimet
WINSTONCH [101]

Answer:

D. 100 cm^2

Step-by-step explanation:

i did this before so ik im right

8 0
2 years ago
A researcher is interested in estimating the mean weight of a semi tracker truck to determine the potential load capacity. She t
FinnZ [79.3K]

Answer:

(19229.11 ,20770.89)

Step-by-step explanation:

We are given the following information:

Sample size, n = 17

Sample mean = 20,000 pounds

Sample standard deviation = 1,500 pounds

Confidence level = 95%

Significance level = 5% = 0.05

95% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 16 and}~\alpha_{0.05} = \pm 2.119  

20000 \pm 2.119(\displaystyle\frac{1500}{\sqrt{17}} ) = 20000 \pm 770.89 = (19229.11 ,20770.89)  

4 0
3 years ago
Haley is camping and needs to go from the campground to the waterfall. She hikes 3 miles north and 7 miles east. What is the sho
miskamm [114]

Answer:

7.61 miles

Step-by-step explanation:

Given that,

Haley hikes 3 miles north and 7 miles east.

We need to find the shortest distance from the campground to the waterfall. Let the distance is D.

It can be calculated as follows :

D=\sqrt{3^2+7^2}\\D=7.61\ miles

So, the shortest distance from the campground to the waterfall is 7.61 miles.

3 0
3 years ago
An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Ghella [55]

Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

C) P(R&B) = 3/5 = 60%

Step-by-step explanation:

C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5

3 0
3 years ago
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