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r-ruslan [8.4K]
2 years ago
10

Multiply. (3 - 4i)(5 + 2i)

Mathematics
1 answer:
vaieri [72.5K]2 years ago
5 0

Answer:

15 - 14i - 8i

Step-by-step explanation:

         5      2i

3       15      6i

-4i   -20i   -8i

15 + 6i - 20i - 8i

15 - 14i - 8i

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Rewrite using a single exponent.<br> 53.53
Helga [31]

Answer:

{5}^{6} \:  \: or \:  \:  {25}^{3}  = 15625

Step-by-step explanation:

{5}^{3}  \times  {5}^{3}

Here we can solve this in 2 ways ,

Method 1 :

{5}^{3}  \times  {5}^{3}

Here the bases are equal. So,

=  >   {5}^{3 + 3}  =  {5}^{6}  = 15625

Method 2 :

{5}^{3}  \times {5}^{3}

Here the exponents are same. So,

=  >  {(5 \times 5)}^{3}  =  {25}^{3}  = 15625

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Answer:

EG = 16 and FH =22

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other

so 2a  = 3b+2

and 2a+3 = 6b-1

We know have a system of equations to solve

2a  = 3b+2

 2a+3 = 6b-1

Subtract 3 from each side

2a+3-3 = 6b-1-3

2a = 6b -4

Now we can set the 2 equations equal  ( 2a  = 3b+2  and 2a = 6b -4)

3b+2 = 6b-4

Subtract 3b from each side

3b-3b+2 = 6b-3b-4

2 = 3b-4

Add 4 to each side

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6 = 3b

Divide by 3

6/3 = 3b/3

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We want to find a

2a  = 3b+2

Substitute in b=2

2a = 3(2) + 2

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Divide by 2

2a/2 =8/2

a = 4

Now that we know a and b

EG = 2a + 3b+2

    = 2(4) + 3(2)+2

   = 8+6+2

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FH = 2a+3 + 6b-1

    = 2(4) +3 +6(2)-1

    = 8+3+12-1

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N = 9

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more help:

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